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MArishka [77]
3 years ago
7

100 POINTS? HELP ME ASAP

Mathematics
2 answers:
dolphi86 [110]3 years ago
8 0

Answer:

A. x^(3/5) = y.

Step-by-step explanation:

Given x^3 = y^5

y = 5th root of x^3

y = x^(3/5)  answer.

lukranit [14]3 years ago
5 0

Answer:

I think its 73

Step-by-step explanation:

Iam not sure fif iam wrong please corerct me

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x = c1 cos(t) + c2 sin(t) is a two-parameter family of solutions of the second-order DE x'' + x = 0. Find a solution of the seco
igomit [66]

Answer:

x=-cos(t)+2sin(t)

Step-by-step explanation:

The problem is very simple, since they give us the solution from the start. However I will show you how they came to that solution:

A differential equation of the form:

a_n y^n +a_n_-_1y^{n-1}+...+a_1y'+a_oy=0

Will have a characteristic equation of the form:

a_n r^n +a_n_-_1r^{n-1}+...+a_1r+a_o=0

Where solutions r_1,r_2...,r_n are the roots from which the general solution can be found.

For real roots the solution is given by:

y(t)=c_1e^{r_1t} +c_2e^{r_2t}

For real repeated roots the solution is given by:

y(t)=c_1e^{rt} +c_2te^{rt}

For complex roots the solution is given by:

y(t)=c_1e^{\lambda t} cos(\mu t)+c_2e^{\lambda t} sin(\mu t)

Where:

r_1_,_2=\lambda \pm \mu i

Let's find the solution for x''+x=0 using the previous information:

The characteristic equation is:

r^{2} +1=0

So, the roots are given by:

r_1_,_2=0\pm \sqrt{-1} =\pm i

Therefore, the solution is:

x(t)=c_1cos(t)+c_2sin(t)

As you can see, is the same solution provided by the problem.

Moving on, let's find the derivative of x(t) in order to find the constants c_1 and c_2:

x'(t)=-c_1sin(t)+c_2cos(t)

Evaluating the initial conditions:

x(0)=-1\\\\-1=c_1cos(0)+c_2sin(0)\\\\-1=c_1

And

x'(0)=2\\\\2=-c_1sin(0)+c_2cos(0)\\\\2=c_2

Now we have found the value of the constants, the solution of the second-order IVP is:

x=-cos(t)+2sin(t)

3 0
3 years ago
|x+3| if x>5
svlad2 [7]
What are you looking for?
6 0
3 years ago
Carpet for a room measure 3 m by 2 m how many square meters do I need
Mazyrski [523]
3•2= 6 sqare meters
7 0
3 years ago
Which of the following sets of measurements could be the side lengths of a right triangle?
nordsb [41]
Would have to be C due to all the other numbers not adding up to be a right angle
3 0
3 years ago
Read 2 more answers
Please help!! <br><br>is it 16?​
sweet-ann [11.9K]

Answer:

area of trapezium: -

formula...

½(sum of parallel sides)×height=area

=>240=½(12+x)×12

=>240=(12+x)×6

=>240=60+6x

=>6x=240-60

=>6x=180

=>x=180/6

=>x=30cm

therefore, the value of x is 30 cm.

Step-by-step explanation:

hope it helps u

6 0
2 years ago
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