Answer:
- <u>The energy change would be 46kJ</u>
- <u>The energy would be absorbed</u>
Explanation:
The <em>energy change </em>during a chemical reation, i.e. the reaction energy, is equal to the chemical energy stored in the<em> bonds of the products </em>less the chemical energy stored in the <em>bonds of the reactants</em>.
Hence:
- <em>Energy change</em> = 478 kJ - 432kJ = 46kJ
The change is positive, this is, the chemical energy of the products is greater than the chemical energy of the reactants.
That corresponds to the second graph, where the level of the energy of the products in the graph is higher than the level of the energy of the reactants. Therefore, the conclusion is that the reaction <em>absorbed energy</em> and it is endothermic.
b..a harmless organism imitating the look of a harmful organism
Explanation:
A harmless organism imitating the look of a harmful organism is one example of mimicry that enables prey species avoid predation.
Prey are smaller and less harmful organisms often hunted by larger organisms usually carnivores.
Mimicry is a form of evolutionary adaptation process in which two organisms of the same specie or different species tends to look alike.
It is a subtle defense mechanism developed by organism over an extended period of time.
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Adaptation brainly.com/question/11105547
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11m if you add 6+5 you get 11 but of course you need the “m” in the mix so 11m but correct me if I’m wrong.
I am walking to the end of the room holding three textbooks.
Playing tug of war
Moving boxes to move out of your house
Answer:
d) The 2 athletes reach the same height, because the athletes run with the same speed.
Explanation:
In the whole process , kinetic energy is converted into potential energy .
1/2 m v² = mgh
v² = 2gh
h = v² / 2g
In this expression we see that height attained does not depend upon mass of the object . At the same time it also makes it clear that it depends upon velocity . As the velocity in both the cases are same , height attained by both of them will be same. Hence option d ) is correct.
