Answer:
East
Explanation:
In circular motion, the velocity of the object will always be tangential to the radius of the circle. In this case, since the car is at the northernmost point of the circular track, then it must be moving right or towards the east, no matter what the acceleration might be at that very moment or what the radius of the track is. If it's moving clockwise, then it moves right (towards the east).
<u>Answer:</u>
The acceleration of the plane and the time required to reach this speed is (a)= 7.5 and time(t) = 20 seconds
<u>Explanation: </u>
Given data Initial velocity = 0
Final velocity () = 150 m/second
Distance (d) = 1500 m
We have the formula,
which gives = 0+2a(1500)
22500 = 3000 a
acceleration (a) = 7.5
150 = 7.5 t
t= 150/7.5 = 20
t = 20 seconds.
Answer
given,
position of particle
x(t)= A t + B t²
A = -3.5 m/s
B = 3.9 m/s²
t = 3 s
a) x(t)= -3.5 t + 3.9 t²
velocity of the particle is equal to the differentiation of position w.r.t. time.
------(1)
velocity of the particle at t = 3 s
v = -3.5 + 7.8 x 3
v = 19.9 m/s
b) velocity of the particle at origin
time at which particle is at origin
x(t)= -3.5 t + 3.9 t²
0 = t (-3.5 + 3.9 t )
t = 0,
t = 0 , 0.897 s
speed of the particle at t = 0.897 s
from equation (1)
v = -3.9 + 7.8 t
v = -3.9 + 7.8 x 0.897
v = 3.1 m/s