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Romashka-Z-Leto [24]

3 years ago

12

A car is traveling clockwise around a circular racetrack of radius 1440m. When the car is at the northernmost point of the circl

e, it has a speed of 36 m/s and is slowing down at a rate of 1.2m/s^2. What is the direction of the velocity the car has?

1 answer:

JulijaS [17]3 years ago

7 0

Answer:

East

Explanation:

In circular motion, the velocity of the object will always be tangential to the radius of the circle. In this case, since the car is at the northernmost point of the circular track, then it must be moving right or towards the east, no matter what the acceleration might be at that very moment or what the radius of the track is. If it's moving clockwise, then it moves right (towards the east).

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Water is boiled at sea level in a coffeemaker equipped with an immersion-type electric heating element. The coffee maker contain

Luden [163]

Answer:

$P=1362\ W$

$t'=251.659\ s$ is time required to heat to boiling point form initial temperature.

Explanation:

Given:

initial temperature of water, $T_i=18^{\circ}C$

time taken to vapourize half a liter of water, $t=18\ min=1080\ s$

desity of water, $\rho=1\ kg.L^{-1}$

So, the givne mass of water, $m=1\ kg$

enthalpy of vaporization of water, $h_{fg}=2256.4\times 10^{-3}\ J.kg^{-1}$

specific heat of water, $c=4180\ J.kg^{-1}.K^{-1}$

Amount of heat required to raise the temperature of given water mass to 100°C:

$Q_s=m.c.\Delta T$

$Q_s=1\times 4180\times (100-18)$

$Q_s=342760\ J$

Now the amount of heat required to vaporize 0.5 kg of water:

$Q_v=m'\times h_{fg}$

where:

$m'=0.5\ kg=$ mass of water vaporized due to boiling

$Q_v=0.5\times 2256.4$

$Q_v=1.1282\times 10^{6}\ J$

Now the power rating of the boiler:

$P=\frac{Q_s+Q_v}{t}$

$P=\frac{342760+1128200}{1080}$

$P=1362\ W$

Now the time required to heat to boiling point form initial temperature:

$t'=\frac{Q_s}{P}$

$t'=\frac{342760}{1362}$

$t'=251.659\ s$

6 0

3 years ago

A magnetic field is uniform over a flat, horizontal circular region with a radius of 1.50 mm, and the field varies with time. In

Daniel [21]

Answer: $81.57\mu V$

Explanation:

Given

radius of circular region r=1.50 mm

$A=\pi r^2=7.069\times 10^{-6}\ m^2$

Magnetic Field $B=1.50\ T$

time t=130 ms

Flux is given by

$\phi =B\cdot A$

change in Flux $d\phi =(B_f-B_i)A$

Emf induced is $e=\frac{\mathrm{d} \phi}{\mathrm{d} t}$

$e=\frac{(1.5)\cdot 7.069\times 10^{-6}}{130\times 10^{-3}}$

$e=81.57 \mu V$

3 0

3 years ago

A uniform beam resting on two pivots has a length L = 6.00 m and weight M = 220 lbs. The pivot under the left end exerts a norma

gulaghasi [49]

Answer:

x = 4,138 m

Explanation:

For this exercise, let's use the rotational equilibrium equation.

Let's fix our frame of reference on the left side of the pivot, the positive direction for anti-clockwise rotation

∑ τ = 0

n₁ 0 - W L / 2 + n₂ 4 - W_woman x = 0

x = (- W L / 2 + 4n2) / W_woman

Let's reduce the magnitudes to the SI System

M = 6 lbs (1 kg / 2.2 lb) = 2.72 kg

M_woman = 130 lbs = 59.09 kg

Let's write the transnational equilibrium equation

n₁ + n₂ - W - W_woman = 0

n₁ + n₂ = W + W_woman

n₁ + n₂ = (2.72 + 59.09) 9.8

At the point where the system begins to rotate, pivot 1 has no force on it, so its relation must be zero (n₁ = 0)

n₂ = 605,738 N

Let's calculate

x = (-2.72 9.8 6/2 + 4 605.738) / 59.09 9.8

x = 4,138 m

4 0

3 years ago

What are some charactersitics of pressure waves

True [87]

Soft target by impact and its contribution to indirect bone fractures.

7 0

3 years ago

Which describes the relationship between photon energy and the color of light?

Andrew [12]

Photon energy is directly proportional to the frequency of electromagnetic radiation.
(That would also mean that it's inversely proportional to the wavelength.)

So the photon energy increases as you scan the chart of visible colors
moving from the red end of the rainbow to the blue end.

3 0

3 years ago

Read 2 more answers