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LekaFEV [45]
3 years ago
10

Suppose a large power plant generates electricity at 12.0 kV. Its old transformer once converted this voltage to 365 kV. The sec

ondary coil of this transformer is being replaced so that its output can be 760 kV for more efficient cross-country transmission on upgraded transmission lines. Randomized Variables V1
Part (a) What is the ratio of turns in the new secondary to the number of turns in the old secondary? 33% Part (b) What is the ratio of new current output to the old current output for the same power input to the transformer?
Physics
1 answer:
Yuki888 [10]3 years ago
6 0

Answer:

\dfrac{N_s}{N_p}=2.08219

\dfrac{I_{sn}}{I_{so}}=0.48289

Explanation:

V denotes voltage

I denotes current

p denotes primary

s denotes secondary

o denotes old

n denotes new

N denotes number of turns

For transformers we have the following relation

\dfrac{V_s}{V_p}=\dfrac{N_s}{N_p}\\\Rightarrow \dfrac{N_s}{N_p}=\dfrac{760}{365}\\\Rightarrow \dfrac{N_s}{N_p}=2.08219

The required ratio is \dfrac{N_s}{N_p}=2.08219

For current

\dfrac{I_{so}}{I_{sn}}=\dfrac{V_{sn}}{V_{sn}}\\\Rightarrow \dfrac{I_{sn}}{I_{so}}=\dfrac{367}{760}\\\Rightarrow \dfrac{I_{sn}}{I_{so}}=0.48289

The required ratio is \dfrac{I_{sn}}{I_{so}}=0.48289

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