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LekaFEV [45]
2 years ago
10

Suppose a large power plant generates electricity at 12.0 kV. Its old transformer once converted this voltage to 365 kV. The sec

ondary coil of this transformer is being replaced so that its output can be 760 kV for more efficient cross-country transmission on upgraded transmission lines. Randomized Variables V1
Part (a) What is the ratio of turns in the new secondary to the number of turns in the old secondary? 33% Part (b) What is the ratio of new current output to the old current output for the same power input to the transformer?
Physics
1 answer:
Yuki888 [10]2 years ago
6 0

Answer:

\dfrac{N_s}{N_p}=2.08219

\dfrac{I_{sn}}{I_{so}}=0.48289

Explanation:

V denotes voltage

I denotes current

p denotes primary

s denotes secondary

o denotes old

n denotes new

N denotes number of turns

For transformers we have the following relation

\dfrac{V_s}{V_p}=\dfrac{N_s}{N_p}\\\Rightarrow \dfrac{N_s}{N_p}=\dfrac{760}{365}\\\Rightarrow \dfrac{N_s}{N_p}=2.08219

The required ratio is \dfrac{N_s}{N_p}=2.08219

For current

\dfrac{I_{so}}{I_{sn}}=\dfrac{V_{sn}}{V_{sn}}\\\Rightarrow \dfrac{I_{sn}}{I_{so}}=\dfrac{367}{760}\\\Rightarrow \dfrac{I_{sn}}{I_{so}}=0.48289

The required ratio is \dfrac{I_{sn}}{I_{so}}=0.48289

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An initially stationary object experiences an acceleration of 6 m/s2 for a time of 15 s. How far will it travel during that time
andrew-mc [135]

Answer:

The object will travel 675 m during that time.

Explanation:

A body moves with constant acceleration motion or uniformly accelerated rectilinear motion (u.a.r.m) when the path is a straight line, but the velocity is not necessarily constant because there is an acceleration.

In other words, a body performs a u.a.r.m when its path is a straight line and its acceleration is constant. This implies that the speed increases or decreases uniformly.

In this case, the position is calculated using the expression:

x = xo + vo*t + ½*a*t²

where:

  • x0 is the initial position.
  • v0 is the initial velocity.
  • a is the acceleration.
  • t is the time interval in which the motion is studied.

In this case:

  • x0= 0
  • v0= 0  because the object is initially stationary
  • a= 6 \frac{m}{s^{2} }
  • t= 15 s

Replacing:

x= 0 + 0*15 s + ½*6 \frac{m}{s^{2} }*(15s)²

Solving:

x=½*6 \frac{m}{s^{2} }*(15s)²

x=½*6 \frac{m}{s^{2} }*225 s²

x= 675 m

<u><em> The object will travel 675 m during that time.</em></u>

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2 years ago
What study did james e hansen focus on
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James E. Hansen studied climate change
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Jeremiah is conducting an investigation about the water cycle. He is given the following
Vlada [557]

The water cycle outlines the continuous water movement in liquid, solid and gaseous state between locations on the Earth's surface.

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Arrangement description and Processes;

The processes of the water cycle includes;

  • Evaporation;
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The arrangement of the materials is as follows;

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  • Cover the glass jar by wrapping the plastic wrap (the sky) around it to prevent the escape of water vapor when the water is hot.

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Observed processes;

The processes demonstrated by the above experiment includes;

1) Evaporation: As the water in the glass jar becomes warmer, the level of the water in the jar can be observed to decrease slightly due to evaporation

2) Condensation: Fog formation, Clouds

When hotter, the water surface as seen through the clear plastic wrap becomes less clearer due to evaporation, and condensation of the vapor while floating above the water surface, similar to the clouds seen in the sky.

3. Precipitation: Rain;

The clear plastic wrap covering the top of the glass jar, prevents the movement of the vapor further away, such that the tiny condensed vapor gather together, to form big droplets under the plastic wrap that falls back into the jar, which is similar to the process of rainfall

The above processes are repeated as more water evaporates from the jar condenses on the plastic wrap and falls back into the jar, showing the process by which water is recycled from the lake into the atmosphere and back to the lake.

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4 0
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Amoebas have projections called pseudopods. What are they used for
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Answer:

Amoebas have projections called pseudopods

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<span>a driver's foot off the accelerator and on the break pedal. C</span>
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