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ira [324]
3 years ago
9

A rock is thrown downward from the top of a 36.2-m-tall tower with an initial speed of 13 m/s. Assuming negligible air resistanc

e, what is the speed of the rock just before hitting the ground
Physics
1 answer:
vekshin13 years ago
4 0

Explanation:

u = 13m/s

s = 36.2m

a = 9.81m/s² (positive because it is acting on the same direction as the velocity)

Using Kinematics, we have v² = u² + 2as = (13)² + 2(9.81)(36.2) = 879.244m²/s². => v = 29.65m/s.

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If two connected points objects pass through the same set of three points, the shapes created by each will be identical, regardl
djverab [1.8K]

Answer:

True

Explanation:

It Depends on the order in which each object was plotted, if two connected points objects pass through the same set of three points, the shapes created by each point may be different

7 0
3 years ago
A car has a kinetic energy of 103kJ.
sergij07 [2.7K]

Answer: 1200kg

Explanation:

KE = (1/2)mv^2

103kJ = 103000J

103000J = (1/2) * m * (13.1m/s)^2

Solve for m

5 0
3 years ago
A positively-charged object with a mass of 0.129 kg oscillates at the end of a spring, generating ELF (extremely low frequency)
9966 [12]

Answer:308 N/m

Explanation:

Given

mass\left ( m\right )=0.129 kg

wavelength\left ( \lambda \right )=3.86\times 10^7

We know frequency =\frac{c}{\lambda }=\frac{3\times 10^8}{3.86\tmes 10^7}

f=7.772 Hz

As the frequency of radio waves is same as the frequency at which object oscillates

f=\frac{1}{2\pi }\sqrt{\frac{k}{m}}

7.772=\frac{1}{2\pi }\sqrt{\frac{k}{0.129}}

7.772\times 2\times \pi =\sqrt{\frac{k}{0.129}}

k=307.70\approx 308 N/m

7 0
3 years ago
What does a wave carry?<br> go
Marysya12 [62]

Answer:

Waves carry energy from one place to another. Because waves carry energy, some waves are used for communication, eg radio and television waves and mobile telephone signals. There are many types of waves including sound waves, water waves and all the parts of the electromagnetic spectrum.

Explanation:

5 0
4 years ago
Read 2 more answers
You have a length of tubing that is closed at one end. You cut the tubing into two pieces of unequal length, giving you a tube o
umka21 [38]

Answer:

The funda mental frequency of the original tube is 182Hz.

Explanation:

See the attachment for the calculation steps.

In order to calculate the fundamental frequency of the original closed tube we need to find the length of the tube which is equal to the sum of the lengths of the two new tubes.

For closed tubes

f = nv/4L (n = 1, 3, 5,...n)

f = nv/2L (n = 1, 2, 3,...n)

The details of calculation can be found below in the attachment.

4 0
3 years ago
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