Answer:
25.59 m/s²
Explanation:
Using the formula for the force of static friction:
--- (1)
where;
static friction force
coefficient of static friction
N = normal force
Also, recall that:
F = mass × acceleration
Similarly, N = mg
here, due to min. acceleration of the car;
From equation (1)
However, there is a need to balance the frictional force by using the force due to the car's acceleration between the quarter and the wall of the rocket.
Thus,
where;
and g = 9.8 m/s²
Answer:
F = 0.078N
Explanation:
In order to calculate the magnitude of the force on the wire you first calculate the magnitude of the magnetic field generated by the solenoid, by using the following formula:
(1)
μo: magnetic permeability of vacuum = 4π*10^-7 T/A
N: turns of the solenoid = 580
i: current in the solenoid = 36A
L: length of the solenoid = 18cm = 0.18m
You replace the values of all parameters in the equation (1):
Next, you calculate the force exerted on the wire, by using the following formula:
(2)
i: current in the wire = 27A
L: length of the wire that perceives the magnetic field (the same as the radius of the solenoid) = 2.0 cm = 0.02m
θ: angle between wire and the direction of B
B: magneitc field in the solenoid = 0.145T
The direction of the wire are perpendicular to the direction of the magnetic field, hence, the angle is 90°.
You replace the values of the parameters in the equation (2):
The magnitude of the force on the wire is 0.078N