Answer:
The acceleration of the sliding toboggan is, a = 4.9 m/s²
Explanation:
Given data,
The total weight of the toboggan, W = 1300 N
The slope is, Ф = 30°
The acceleration of a body under the influence of the gravitational field does not depend on its mass, size and shape in the absence of the air resistance.
Therefore,
The acceleration of the toboggan is given by the formula,
a = g Sin Ф
Substituting the given values in the above equation,
a = 9.8 x Sin 30°
= 4.9 m/s²
Hence, the acceleration of the sliding toboggan is, a = 4.9 m/s²
Answer:
The answer is C "think about the problem first, systematically consider all factors, and form a hypothesis"
Explanation:
In physics there is some basic fomula that sir Isacc Newton proposed under the topic of motion. The three formulas are below;
<em>1) v=u+at</em>
<em>2)v^2=u^2+2as</em>
<em>3)s=ut+(1/2)(at^2)</em>
the variables are explained below;
u= initial velocity of the body
a=acceleration/Speed of the body
t= time taken by the body while travelling
s= displacement of the body.
Therefore to solve keatons problem, the factors(variables) in the formulas above need to be systematically considered. Since the ball was dropped from the top of the building, the initial velocity is 0 because the body was at rest. Also the acceleration will be acceleration due to gravity (9.8m/s^2)
I just did this last semester... I know this is wave height!!
Answer:
1D
2C
3C
4C
5D
6D
7D
8D
9B
Explanation:
better give me points X﹏X
Take east to be the positive direction. Then the resultant force from adding <em>F</em>₁ and <em>F</em>₂ is
<em>F</em>₁ + <em>F</em>₂ = (-45 N) + 63 N = 18 N
which is positive, so it's directed east.
To this we add a third force <em>F</em>₃ such that the resultant is 12 N pointing west, making it negative, so that
18 N + <em>F</em>₃ = -12 N
<em>F</em>₃ = -30 N
So <em>F</em>₃ has a magnitude of 30 N and points west.
