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zhenek [66]
3 years ago
5

How does energy relate to force?

Physics
1 answer:
ioda3 years ago
4 0

Answer:work is force times distance

Explanation:to create a force u need energy and the greater the energy the greater the force is applied to an object.

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A scientific study is repeated by four different groups. Only two groups get the same results. Are the data reproducible?
tangare [24]
No, one more group must get the same result as the other group. This will make it more reliable and reproducible.
4 0
3 years ago
How long will it take for a rock to fall 12 meters?
Amiraneli [1.4K]

Answer:

approximately 5.8 seconds

Explanation:

if you where to time how fast a rock would fall 12 meters it would approximately be 5.8 seconds

6 0
3 years ago
Two people are standing on a 1.75-m-long platform, one at each end. The platform floats parallel to the ground on a cushion of a
Fiesta28 [93]

Answer:

0.05312 m

Explanation:

Given:

Length of platform L = 1.75 m

mass of ball m_b = 5.76 kg

mass of (people + platform) m_p = 184 kg

Initial Velocity of ball V_i,b = 0

Initial Velocity of ball (people + platform) V_i,p = 0

Find:

How far does the platform recoils to rest

Solution:

Using the conservation of momentum on ust before and after the ball was thrown P_i = P_f :

Where, P_i = 0 (initially at rest)

P_f = m_p*V_f,p + m_b * V_f,b

0 = m_p*V_f,p + m_b * V_f,b

V_f,p = - (m_b /m_p) * V_f,b

V_f,p = - (5.76 / 184)*V_f,b

V_f,p = - 0.0313*V_f,b   ....1

The time the ball is in air:

t = L / (V_f,b - V_f,p)   ...2

The distance that the platform moves d:

d = V_f,p *t  ....3

Substitute 2 into 3

d = V_f,p*L /(V_f,b - V_f,p)   .... 4

Solve 1 and 4 simultaneously :

d = - m_b*L / (m_b + m_p)

d = - 5.76*1.75 / (5.76 + 184)

d = -0.05312 m

The platform moves 0.05312 m to the opposite to which the ball is thrown.

5 0
3 years ago
A golfer collected data on the distance a golf cart traveled in a straight line and plotted it on a graph
devlian [24]

Answer:

The cart moved away from the starting point between 8 s and 10 s.

Explanation:

Given that :

Which of these does NOT describe the cart’s motion on this graph?

The cart was at rest between 5 s and 7 s : From the distance of golf cart Vs time graph ; the car was at rest between 5s and 7s as the graph was flat with that time interval, meaning there was no change in distance.

The cart moved toward the starting point between 7 s and 12 s. : The graph depicts a negative slope at this time interval as the distance from starting point fell from about 26 m to 10 m

The cart moved away from the starting point between 8 s and 10 s. : At this time interval, the cart moved towards the starting not and not away. This could be seen in the decrease in Distance from starting point between the tune interval.

The cart moved away from the starting point between 2 s and 5 s. - - > The cart moved away from the starting point, with the positive slope signifying an increase in distance.

Therefore, The cart moved away from the starting point between 8 s and 10 s does not describe the motion of the cart on the graph.

5 0
3 years ago
HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
stiks02 [169]

Answer:

oop i cant see the anwer choices correctly

Explanation:

8 0
3 years ago
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