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lukranit [14]
3 years ago
9

An empty container has a mass of 3 g. When it is filled with 5 cm3 of a liquid,

Physics
1 answer:
IrinaK [193]3 years ago
3 0

Answer:

THE MASS OF THE LIQUID IS 22.5 g

Explanation:

Density = 0.180 g/cm3

Side length = 5 cm

Mass = unknown

To calculate the mass of the liquid, we use the formula:

Mass = density * volume

Volume of a cube or cuboid container = l^3

Volume = 5 ^3 = 125 cm3

So therefore, the mass of the liquid is:

Mass = 0.180 * 125

Mass = 22.5 g

In conclusion, the mass of the liquid in the container is 22.5 g

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a straight line on a graph means there is a _________ relationship between the dependent variable and the independent variable
Nady [450]

By definition this is a linear relationship.

4 0
3 years ago
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A ball is thrown straight up. It passes a 2.00-m-high window 7.50 m off the ground on its path up and takes 1.30 s to go past th
OLga [1]

Answer:

u =  13.67 m/s

Explanation:

given,

window height = 2 m

window is 7.5 m off the ground on its path up

total distance from the ground to pass the window = 2 + 7.5 = 9.5 m

time taken to go past the window = 1.30 s

using equation of motion

S = u t +\dfrac{1}{2}gt^2

(2+7.5)= u\times 1.3 -0.5\times 9.8\times 1.3^2

u\times 1.3 = 9.5 + 8.281

u =  13.67 m/s

hence, the initial velocity of the  ball is equal to 13.67 m/s

5 0
3 years ago
A small mailbag is released from a helicopter that is descending steadily at 2.00 m/s. After 5.00s what is the speed of the mail
grandymaker [24]
The acceleration of gravity (on Earth) is 9.8 m/s² downward.

This means that every falling object gains 9.8 m/s more downward speed
every second that it falls.

In 5 seconds of falling, it gains (5 x 9.8 m/s) = 49 m/s of downward speed.

If it was already descending at 2.0 m/s at the beginning of the 5 sec,
then at the end of the 5 sec it would be descending at

                                 (2 m/s  +  49 m/s)  =  51 m/s .
7 0
3 years ago
For the material in the previous question that yields at 200 MPa, what is the maximum mass, in kg, that a cylindrical bar with d
Sedaia [141]

Answer:

The maximum mass the bar can support without yielding = 32408.26 kg

Explanation:

Yield stress of the material (\sigma) = 200 M Pa

Diameter of the bar = 4.5 cm = 45 mm

We know that yield stress of the bar is given by the formula

                Yield Stress = \frac{Maximum load}{Area of the bar}

⇒                                \sigma = \frac{P_{max} }{A}  ---------------- (1)

⇒ Area of the bar (A) = \frac{\pi}{4} ×D^{2}

⇒                            A  = \frac{\pi}{4} × 45^{2}

⇒                            A = 1589.625 mm^{2}

Put all the values in equation (1) we get

⇒ P_{max} = 200 × 1589.625

⇒ P_{max} = 317925 N

In this bar the P_{max} is equal to the weight of the bar.

⇒ P_{max} = M_{max} × g

Where M_{max} is the maximum mass the bar can support.

⇒ M_{max} = \frac{P_{max} }{g}

Put all the values in the above formula we get

⇒ M_{max} = \frac{317925}{9.81}

⇒ M_{max} = 32408.26 Kg

There fore the maximum mass the bar can support without yielding = 32408.26 kg

3 0
4 years ago
Machines
Ainat [17]

Explanation:

Hey there!!

Here, Given is,

Efficiency = 75%

VR = no. of pulleys = 5

Now,

effeciency =  (\frac{ma}{vr} ) \times 100\%

75\% =  \frac{ma}{5}  \times 100\%

100% ma = 75%×5

ma =  \frac{75\% \times5}{100\%}

ma =  \frac{375\%}{100\%}

Therefore, MA is 3.75.

<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

3 0
3 years ago
Read 2 more answers
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