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lukranit [14]
3 years ago
9

An empty container has a mass of 3 g. When it is filled with 5 cm3 of a liquid,

Physics
1 answer:
IrinaK [193]3 years ago
3 0

Answer:

THE MASS OF THE LIQUID IS 22.5 g

Explanation:

Density = 0.180 g/cm3

Side length = 5 cm

Mass = unknown

To calculate the mass of the liquid, we use the formula:

Mass = density * volume

Volume of a cube or cuboid container = l^3

Volume = 5 ^3 = 125 cm3

So therefore, the mass of the liquid is:

Mass = 0.180 * 125

Mass = 22.5 g

In conclusion, the mass of the liquid in the container is 22.5 g

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As the moon revolves around the earth,it also rotated on its axis why is that the same side of the moon is always visible from e
Alina [70]

Answer:

Explanation:

Our lunar companion rotates while it orbits Earth. It's just that the amount of time it takes the moon to complete a revolution on its axis is the same it takes to circle our planet — about 27 days. As a result, the same lunar hemisphere always faces Earth.

7 0
3 years ago
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A large, simple pendulum is on display in the lobby of the United Nations building. If the pendulum is 18.5 m in length, what is
zhannawk [14.2K]

Answer:

     t = 1,144 s

Explanation:

The simple pendulum consists of an inextensible string with a mass at the tip, the angular velocity of this is

     w = √( L / g)

The angular velocity is related to the frequency and period

     w = 2π f

      f = 1 / T

     w = 2π / T

Let's replace

     2π / T = √ (L / g)

     T = 2π √ (g / L)

Let's calculate

     T = 2π √ (9.81 / 18.5)

     T = 4,576 s

The definition of period in the time it takes the ball to come and go to a given point (a revolution) in our case we go from the end to the middle point that is a quarter of the path

     t = T / 4

     t = 4,576 / 4

     t = 1,144 s

6 0
3 years ago
Porque deja de funcionar una estufa electrica cuando la electricidad es excesiva??
Brums [2.3K]
<h3>Porque deja de funcionar una estufa electrica cuando la electricidad es excesiva?</h3>

  • Es normal que los quemadores superiores de una estufa eléctrica o una estufa se enciendan y apaguen en configuraciones distintas a Hi. El quemador se encenderá y apagará más de lo normal cuando se utilizan cacerolas que no son planas o que son del tamaño incorrecto para el quemador.

<h2>☆彡Hanna</h2>

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7 0
3 years ago
Read 2 more answers
0.5-lbm of a saturated vapor is converted to asaturated liquid by being cooled in a weighted piston-cylinder device maintained a
klio [65]

Answer:

The boiling point temperature of this substance when its pressure is 60 psia is  480.275 R

Explanation:

Given the data in the question;

Using the Clapeyron equation

(\frac{dP}{dT} )_{sat } = \frac{h_{fg}}{Tv_{fg}}

(\frac{dP}{dT} )_{sat } = \frac{\frac{H_{fg}}{m} }{T\frac{V_{fg}}{m} }

where h_{fg is the change in enthalpy of saturated vapor to saturated liquid ( 250 Btu

T is the temperature ( 15 + 460 )R

m is the mass of water ( 0.5 Ibm )

V_{fg is specific volume ( 1.5 ft³ )

we substitute

(\frac{dP}{dT} )_{sat } =( \frac{250Btu\frac{778Ibf-ft}{Btu} }{0.5}) / ( (15+460)\frac{1.5}{0.5})  

(\frac{dP}{dT} )_{sat } = 272.98 Ibf-ft²/R

Now,

(\frac{dP}{dT} )_{sat } = (\frac{P_2 - P_1}{T_2 - T_1})_{sat

where P₁ is the initial pressure ( 50 psia )

P₂ is the final pressure ( 60 psia )

T₁ is the initial temperature ( 15 + 460 )R

T₂ is the final temperature = ?

we substitute;

T_2 = ( 15 + 460 ) + \frac{(60-50)psia(\frac{144in^2}{ft^2}) }{272.98}

T_2 = 475 + 5.2751\\

T_2 = 480.275 R

Therefore, boiling point temperature of this substance when its pressure is 60 psia is  480.275 R

3 0
3 years ago
A diode vacuum tube consists of a cathode and an anode spaced 5-mm apart. If 300 V are applied across the plates. What is the ve
MAXImum [283]

Answer:

Explanation:

There is electric field between the plates whose value is given by the following expression

electric field E =  V /d where V is potential between the plates and d is distance between them

E = 300 / 5 x 10⁻³

=  60 x 10³ N/c

Force on electron = q E where q is charge on the electron

F = 1.6 X 10⁻¹⁹ X 60 X 10³ = 96 X 10⁻¹⁶ N.

Acceleration a = force / mass

a = 96 x 10⁻¹⁶/ mass  = 96 x 10⁻¹⁶ / 9.1 x 10⁻³¹

= 10.55 x 10¹⁵ m / s²

For midway , distance travelled

s =  2.5 x 10⁻³ m

s      =  1\2 a t²

t = \sqrt{\frac{2s}{a\\ } }

= \sqrt{\frac{2\times2.5\times10^{-3}}{ 10.55\times10^{15}}

t = .474 x 10⁻¹⁸ s

For striking the plate time is calculated as follows

t = [tex]\sqrt{\frac{2\times5\times10^{-3}}{ 10.55\times10^{15}}[/tex]

t = 0.67 x 10⁻¹⁸ s

3 0
3 years ago
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