Question

A source of laser light sends rays AB and AC toward two opposite walls of a hall. The light rays strike the walls at points B and C, as shown below:
A source of laser light is at point A on the ground between two parallel walls. The walls are perpendicular to the ground. AB is a ray of light which strikes the wall on the left at point B. The length of AB is 40m. AC is a ray of light which strikes the wall on the right at point C which is 80 m above the ground. The ray AB makes an angle of 60 degrees with the ground. The ray AC makes an angle of 45 degrees with the ground.

What is the distance between the walls?

Answer 1

Answer:

Hence, the distance between two walls is:

100 m.

Step-by-step explanation:

We are asked to find the distance between the two balls.

This could be done if we first find the distance between the first wall and the laser bean=d

and then the second wall and the laser bean=d'

and then add both the distances to find the total distance between the two walls i.e. (d+d')

As the triangle is right triangle so we will use the trignometric identity to find the distance.

The distance between the first wall and laser beam is:

$\cos 60=\dfrac{d}{40}\\\\\dfrac{1}{2}=\dfrac{d}{40}\\\\d=\dfrac{40}{2}=20m$

similarly The distance between the second wall and laser beam is:

$\tan45=\dfrac{80}{d'}\\\\1=\dfrac{80}{d'}\\\\d'=80m$

Hence, the distance between the two walls is:

$d+d'=20+80=100$

Hence, the distance between two walls is:

100 m.