Answer:
Concentration = 0.14 M
Explanation:
Given data:
Volume of base = 19.62 mL
Molarity of base = 0.341 M
Volume of acid = 25.00 mL
Molarity of acids = ?
Solution:
Number of moles of base = Molarity × volume in litter
Number of moles = 0.341 mol/L × 0.02 L
Number of moles = 0.007 mol
Concentration of acid:
Concentration = 1/2 (0.007 mol) / 25 mL × 10⁻³ L/mL
Concentration = 0.0035 mol / 25 × 10⁻³ L
Concentration = 1.4 × 10⁻¹ M
Concentration = 0.14 M
