Can you still identify and tell the appearance of each set of materials why?

Which variable is held constant when testing for the thermal expansion relationship of a gas?

Alenkasestr [34]

pressure is the correct answer

7 0

3 years ago

Read 2 more answers

Discribe how continents and oceans are carried on tectonic plates

Vanyuwa [196]

This question seems to be very basic .the ocean is above the plate, the plate material is heavier than water (it being rock). That's pretty much all of it. The plates grind a little and new land pushes up at plate boundaries but this does not seem to be related. The heavier material is below and the lighter above, those being rock and water respectively.
hope this helped u

7 0

2 years ago

If I have 21 liters of gas held at a pressure of 78 atm and a temperature of 900 K, what will

shusha [124]

Answer:

30.33L

Explanation:

Using Boyle's law which states that the volume of a given mass of gas is inversely proportional to the pressure, provided temperature remains constant and Charles law states that the volume of a given mass of gas is directly proportional to the temperature provided the pressure remains constant

P1V1/T1 = P2V2/ T2

P1 = 78atm, V1 = 21L , T1 = 900K

P2 = 45atm, V2 = ? , T2 =750K

78× 21 / 900 = 45×V2 / 750

1638/900 = 45 V2 / 750

1638×750 = 900×45V2

1228500 = 40500V2

Divide both sides by 40500

1228500÷40500= V2

V2 = 30.33L

I hope this was helpful, please mark as brainliest

6 0

3 years ago

β‑Galactosidase (β‑gal) is a hydrolase enzyme that catalyzes the hydrolysis of β‑galactosides into monosaccharides. A 0.387 g sa

gtnhenbr [62]

Answer:

The molar mass of unknown β‑Galactosidaseis 116,352.97 g/mol.

Explanation:

To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

$\pi=icRT$

where,

$\pi$ = osmotic pressure of the solution = 0.602 mbar = 0.000602 bar

0.000602 bar = 0.000594 atm

(1 atm = 1.01325 bar)

i = Van't hoff factor = 1 (for non-electrolytes)

c = concentration of solute = ?

R = Gas constant = $0.0820\text{ L atm }mol^{-1}K^{-1}$

T = temperature of the solution = $25^oC=[273.15 +25]=298.15 K$

Putting values in above equation, we get:

$0.000594 atm=1\times c\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 298.15 K\\\\c=2.4278\times 10^{-5} mol/L$

The concentration of solute is $2.4278\times 10^{-5} mol/L$

Volume of the solution = V =0.137 L

Moles of β‑Galactosidase = n

$C=\frac{n}{V(L)}$

$n=2.4278\times 10^{-5} mol/L\times 0.137 L$

$n=3.3261\times 10^{-6} mol$

To calculate the molecular mass of solute, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Moles of β‑Galactosidase = $3.3261\times 10^{-6} mol$

Given mass of β‑Galactosidase= 0.387 g

Putting values in above equation, we get:

$3.3261\times 10^{-6} mol =\frac{0.387 g}{\text{Molar mass of solute}}\\\\\text{Molar mass of solute}=116,352.97 g/mol$

Hence, the molar mass of unknown β‑Galactosidaseis 116,352.97 g/mol.

3 0

3 years ago

Consider the reaction between iron (III) oxide, Fe2O3 and carbon monoxide, CO.

Lana71 [14]

Fe2O3 + 3CO --> 2Fe + 3CO2

m(Fe2O3)=213 g
m(CO)=140 g
_______________

n(Fe2O3)=?
m(Fe)=?
n(Fe2O3)=?
n(CO)=?
n(CO2)=?

n(Fe2O3)=m(Fe2O3) / M(Fe2O3)
n(Fe2O3)= 213 g / 159,7 gmol-1 = 1,33 mol

n(CO)= m(CO) / M(CO) n(CO)= 140 g / 28,01 gmol-1 = 4,99 mol

3 0

3 years ago

Can you still identify and tell the appearance of each set of materials why?​

Can you still identify and tell the appearance of each set of materials why?