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Burka [1]
4 years ago
8

$4,000 at 3 % for 4 years

Mathematics
1 answer:
e-lub [12.9K]4 years ago
5 0

Answer:

$600

Step-by-step explanation:


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Solve the rational equation x divided by 6 equals x squared divided by quantity x minus 1 end quantity, and check for extraneous
pychu [463]

Answer:

x = 0 and x = \textrm{negative one fifth}

Step-by-step explanation:

Given:

The rational equation to solve is given as:

\frac{x}{6}=\frac{x^2}{x-1}


We use the cross multiplication rule and multiply the numerators one side with the denominators of the other side. Therefore,

x\times (x-1)=6\times x^2\\x^2-x=6x^2\\\textrm{Bringing all variables to the right side, we get:}\\6x^2-x^2+x=0\\5x^2+x=0\\x(5x+1)=0\\x=0\ or\ 5x+1=0\\x=0\ or\ x=-\frac{1}{5}


Now, for x=0, the rational equation is equal to 0. So, x=0 is a solution.

Also, x=-\frac{1}{5} is also a solution as the equation's denominator is defined at that point.

So, no extraneous solution.

8 0
4 years ago
2
Eddi Din [679]
15 and the error is on step 3

Reasoning:
I’m not certain how they got 1.5 but you basically divide both sides by two, the 2 would be canceled and you would be left with w, divide 30 by 2 and you get w=15, sorry i suck at explaining
5 0
3 years ago
A bowl of fruit is on the table.  It contains 3 apples, 5 oranges, and 2 pears.  Ryan and Kenneth come home from school and, at
Airida [17]
2 out of 8 I think hope it helps
4 0
4 years ago
Find the slope of a line that passes through the points (-3,-1) and (0,-5)
VARVARA [1.3K]
\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%   (a,b)
&({{ -3}}\quad ,&{{ -1}})\quad 
%   (c,d)
&({{ 0}}\quad ,&{{ -5}})
\end{array}
\\\\\\
% slope  = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{-5-(-1)}{0-(-3)}\implies \cfrac{-5+1}{0+3}
\\\\\\
\cfrac{-4}{3}
5 0
3 years ago
If f(x) = 4x - 7 and g(x) = 3x + 9 find (f+g) (5)
babunello [35]

Answer: (f+g)(5)=37

Step-by-step explanation:

(f+g) (5) is the same as saying f(5)+g(5). Since we are given f(x) and g(x), we can use them to solve. There are two ways to solve. One is to find f(5) and g(5), and then add them together. Another way is to do (f+g)(x), then plug in x=5. I will show both methods.

Method 1

f(5)=4(5)-7                       [multiply]

f(5)=20-7                         [subtract]

f(5)=13

g(5)=3(5)+9                     [multiply]

g(5)=15+9                        [add]

g(5)=24

(f+g)(5)=13+24                [add f(5) and g(5)]

(f+g)(5)=37

--------------------------------------------------------------------------------------------------------

Method 2

(f+g)(x)=4x-7+3x+9         [combine like terms]

(f+g)(x)=7x+2

(f+g)(5)=7(5)+2                [plug in x=5]

(f+g)(5)=35+2                  [add]

(f+g)(5)=37

--------------------------------------------------------------------------------------------------------

Now, we know that (f+g)(5)=37. We confirmed this with both methods.

4 0
3 years ago
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