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3 years ago

15

Jim has 9 feet of ribbon he uses 1/3 foot of ribbon to make each bookmark. what is the total number of bookmarks Jim makes with

all 9 feet of ribbon

1 answer:

Orlov [11]3 years ago

6 0

Since there were 9 feet of ribbon and Jim uses 1/3 we are going to do 9/1 * 1/3 and get 3 Jim makes 3 ribbons.

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I need help on this, please hurry and thank you!

inna [77]

Answer:

$A.\ a_n=n^2+1$

Step-by-step explanation:

$Check:$

$a_n=n^2+1\\\\a_1=1^2+1=1+1=2\qquad CORRECT\\\\a_2=2^2+1=4+1=5\qquad CORRECT\\\\a_3=3^2+1=9+1=10\qquad CORRECT\\\\a_4=4^2+1=16+1=17\qquad CORRECT\\\\a_5=5^2+1=25+1=26\qquad CORRECT$

Used PEMDAS:

P Parentheses first

E Exponents (ie Powers and Square Roots, etc.)

MD Multiplication and Division (left-to-right)

AS Addition and Subtraction (left-to-right)

First Power, next Addition

4 0

3 years ago

Read 2 more answers

(Score for Question 2: ___ of 5 points)

GuDViN [60]

Answer:

Answer:

Since you don't show your triangles, I'm guessing it is this one...?

△DWP D = (-2, 4), W = (-1, 2), P = (3, 3)

△MJS M = (-4, -4), J = (-2, -3), S = (-3, 1)

There are 2 steps:

1. 90° counterclockwise rotation about the origin

2. Translation downward 2 units

Step-by-step explanation:

1. 90° counterclockwise rotation about the origin = (x, y) to (-y, x),

D moves from (-2, 4) to (-4, -2)

W moves from (-1, 2) to (-2, -1)

P moves from (3, 3) to (-3, 3)

2. Translation downward 2 units = (x, y) to (x, y-2),

D moves from (-4, -2) to (-4, -4) = M

W moves from (-2, -1) to (-2, -3) = J

P moves from (-3, 3) to (-3, 1) = S

Therefore △DWP IS congruent to △MJS.

4 0

2 years ago

Write the standard form of the equation of the line through the pair of points (6,3) and (-7,7)

timofeeve [1]

Step-by-step explanation:

steps are in the picture above.

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3 0

3 years ago

How many outer atoms and lone pairs are present in a molecule with a square pyramidal shape?

arlik [135]

Answer:

5 Outer and 1 lone pair

Step-by-step explanation:

A square pyramidal shape results when one of the bonds of an octahedron structure is occupied by a lone pair.

Hence there are 5 bonded atoms and one lone pair. The hybridization about the central atom is $sp^{3} d^2$ .

One of the most common example is Xenon tetraflouride. $XeF_4$ . Looking at its structure we can see that it has 5 pairs of outer atoms and one lone pair. With its coordination number 5. The shape of the orbitals is octahedral.

4 0

3 years ago

1. Find the exact value of sin and cos of 195 degrees.

KengaRu [80]

Answer:

Sin195* = - $\frac{\sqrt{6}-\sqrt{2} }{4 }$

Cos195* = - $\frac{\sqrt{6} +\sqrt{2} }{4}$

Step-by-step explanation:

5 0

3 years ago