Answer:
Step-by-step explanation:
Given that
Group Group One Group Two
Mean 26.00 23.00
SD 2.00 4.00
SEM 0.40 1.21
N 25 11
where group I represents female servers and group II male servers.
We have to calculate confidence interval for 90% for difference in means
The mean of Group One minus Group Two equals 3.00
df = 34
standard error of difference = 0.993
t critical = 2.034 for 90% df 34
Hence confid. interval at 90%
=Mean diff ±2.034 * std error of diff
= (0.98, 5.02)
Answer:
x=3
Step-by-step explanation:
We are given the equation
This can be rewritten as
Now using the quotient rule for logarithms we can combine these two
Next we can remove the log by using an inverse operation
Now we can solve for x
Answer:
Step-by-step explanation:
1) D
2) B
3) no solution
y ≤ 0.5x - 4 is area C including the red line
y ≥ 0.5x + 5 is area A including the blue line
Not sure of the answer but i know what factors
p ^2 - 2p
p (p-2)
-q^2 +2q
-q (q-2)
so maybe (p-q) (p-2) (q-2)
The answer to this is x = 2
