I need some help. Can anyone help?

Write this number in words.<br><br> 8,400.9

telo118 [61]

Eight thousand four hundred point nine

5 0

3 years ago

Mr. Ray is trying to determine the median value of the class averages for his math classes. First, he must list the class averag

Neko [114]

a is the answer

all you need to do is place the numbers from the lowest amount to the highest amount :)

7 0

4 years ago

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2. There are 42 persons in a mathematics class, and everyone of them drinks either coffee or grape milk at

Basile [38]

Answer:

1. 8

2. 24

Step-by-step explanation:

The number of persons that drink grape milk only :

18 - 10 = 8

The number of persons that drink coffee :

42 - 8 = 34

The number of persons that drink coffee only :

34 - 10 = 24

5 0

2 years ago

You are given a choice of taking the simple interest on $100,000 invested for 2 years at a rate of 3% or the interest on $100,00

valentinak56 [21]

Answer:

Step-by-step explanation:

the simple interest formula= principal* interest rate*time

simple interest : 100000*%2*2 years

simple interest= 4000 dollars

compound quarterly : A=principal(1+r/4)^t

since it is quarterly and have 4 quarters in a year, and 8 in two years.

compound quarterly: 100000(1+0.03/4)^8=106159.88

it is better to invest with compound interest because it add 6159 dollars in two years to the investment of 100000 dollars.

the difference between the interest: 6159.88-4000=2159.88

5 0

3 years ago

Galena is solving the following system. 3x+2y+3z =5 7x+y +7z=-1 4x-4y-z=-3

babymother [125]

Answer:

She did not multiply equation 3 in step 2 by the correct value.

Step-by-step explanation:

Given:

$3x+2y+3z=5\\7x+y+7z=-1\\4x-4y-z=-3$

In order to solve this, we need to eliminate any one variable and then form a simultaneous equation with the remaining two variables. Then, we nee to solve the simultaneous equation.

Here, Galena is trying to eliminate the variable $z$ first.

Step 1: She multiplies equation (3) by 3 and adds it to equation (1)

Let us multiply equation (3) by 3

$(4x-4y-z=-3)\times 3 = (3\times 4x)-(3\times 4y)-(3\times z)=3\times -3\\(4x-4y-z=-3)\times 3 =12x-12y-3z=-9$

Now, adding this to equation 1 will cancel out z terms.

$12x-12y-3z+3x+2y+3z=-9+5\\(12x+3x)+(-12y+2y)+(3z-3z)=-4\\15x-10y+0=-4$

Now, she need to make one more equation in $x\ and \ y$ .

Step 2: She multiplies equation (3) by -7 and adds it to equation (2)

Multiplying equation (3) by -7 will give,

$(4x-4y-z=-3)\times -7 = (-7\times 4x)-(-7\times 4y)-(-7\times z)=-7\times -3\\(4x-4y-z=-3)\times 3 =-28x+28y+7z=21$

Now, adding this to equation 2 will not cancel out z terms.

$-28x+28y+7z+7x+y+7z=21-1\\(-28x+7x)+(28y+y)+(7z+7z)=20\\-21x+29y+14z=20$

So, she makes mistake in step 2 as the $z$ terms are not being cancelled.

6 0

4 years ago

Read 2 more answers