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harkovskaia [24]
3 years ago
12

An exam worth 269 points contains 36 questions. Some questions are worth 7 points, and the others are worth 8 points. How many 7

point and 8 point questions are on the test?
Mathematics
1 answer:
Nezavi [6.7K]3 years ago
5 0

Answer:

There are 19 questions worth 7 points.

There are 17 questions worth 8 points.

Step-by-step explanation:

Assign variables:

Let x = number of questions worth 7 points.

Let y = number of questions worth 8 points.

First we deal with the number of questions.

There are 36 questions, so our first equation is:

x + y = 36

Now we deal with the points.

x questions worth 7 points each are worth 7x points.

y questions worth 8 points each are worth 8y points.

The total worth of all the questions is 7x + 8y.

The total worth of the exam is 269, so our second equation is

7x + 8y = 269

We have a system of 2 equations in 2 variables.

x + y = 36

7x + 8y = 269

Let's use the substitution method to solve the system of equations.

Solve the first equation for x.

x + y = 36

x = 36 - y

Substitute 36 - y in for x in the second equation.

7x + 8y = 269

7(36 - y) + 8y = 269

Distribute the 7.

252 - 7y + 8y = 269

Combine like terms.

252 + y = 269

Subtract 252 from both sides.

y = 17

There are 17 questions worth 8 points.

x + y = 36

x + 17 = 36

x = 19

There are 19 questions worth 7 points.

Check:

What does 19 questions at 7 points each and 17 questions at 8 points each add to?

19 * 7 + 17 * 8 = 133 + 136 = 269

The points add to 269, so our answer is correct.

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Step-by-step explanation:

only answer that makes sense

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Find the product of (x + 5)2.<br><br> x2 − 10x + 25<br> x2 − 25<br> x2 + 25<br> x2 + 10x + 25
TiliK225 [7]

if the question is (x + 5)^2, the product is x^2 + 10x + 25.

5 0
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A swimming pool is 12.4 feet long and 6.20 feet wide what area does the pool occupy? plz help me
jonny [76]
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4 years ago
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Will mark brainliest! Questions are in the picture!
alexdok [17]

Answer:

52.9 inches .

Step-by-step explanation:

Given that the triangular indentation has an area of 100 in.² and the base and height of this traingle are represented by expressions 3x and x+3 respectively . We need to find out the <u>perimeter </u>to the nearest tenth.

As we know that the area of triangle is ,

\rm\longrightarrow Area_{\triangle}=\dfrac{1}{2}(base)(height)

Substituting the respective values,

\rm\longrightarrow 100\ =\dfrac{1}{2}(x+3)(3x)\\\\\rm\longrightarrow 2(100) = 3x(x+3)\\\\\rm\longrightarrow200 = 3x^2+9x\\\\\rm\longrightarrow 3x^2+9x-200=0

On using the <u>Quadratic</u><u> formula</u> , we have;

\rm\longrightarrow x =\dfrac{-9\pm\sqrt{9^2-4(3)(-200)}}{2(3)} \\\\\rm\longrightarrow x =\dfrac{-9\pm \sqrt{81+1200}}{6}\\\\\rm\longrightarrow x =\dfrac{-9\pm \sqrt{1281}}{6}

On simplifying above , we will get ,

\rm\longrightarrow x = 6.802,-9.802

Since sides can't be negative, therefore,

\rm\longrightarrow\underline{\underline{ x =6.802}}

Therefore ,

  • \rm\longrightarrow Base = 3x =3(6.802)in = 20.406\ in\\
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Next let's find out the <u>hypotenuse </u>using Pythagoras theorem, as ;

\rm\longrightarrow h=\sqrt{ b^2+p^2}\\

\rm\longrightarrow h =\sqrt{ (20.406)^2+(9.802)^2}\\

\rm\longrightarrow h =\sqrt{416.40+96.07}\\

\rm\longrightarrow h = 22.63\ in

Now we may find perimeter as ,

\rm\longrightarrow P = p + b + h \\

\rm\longrightarrow P = (22.63 + 9.802 + 20.406)in.

\\\rm\longrightarrow P = 52.89 \ in.\\

\rm\longrightarrow \underline{\underline{ Perimeter = 52.9\ in .}}

8 0
3 years ago
the number m and 5/8 are additive inverses.drag and drop m to their correct positions on the number line.drag and drop the label
monitta

The additive inverse of a number is that number with its sign changed.

The additive inverse of 5/8 is -5/8, so that is the value of <em>m</em>.

The sum of a number and its additive inverse is <em>zero</em>. (This is actually the definition of <em>additive inverse</em>.)

5/8 is found at 5/8 on the number line.

m is found at -5/8 on the number line.

"sum" is found at 0 on the number line.

3 0
3 years ago
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