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3 years ago

Seventy-five percent of the data falls below what number? 30 12 36 27

Mathematics

2 answers:

padilas [110]3 years ago

8 0

Total number is 40
Percentage asked is 75
$\frac{75}{100} \times 40$
= 30
Therefore the correct answer is 30

ahrayia [7]3 years ago

6 0

Seventy-five percent of the data falls below what number?

In the box and whisker plot, the first dot represents the minimum value in data set.

In our box and whisker plot, 6 is the minimum value.

The next dot is Q1, Quartile1. The 25% values of data set are within 6 and 12.

The next dot is Q2, or Median. The 50% values of data set are within 6 and 20.

The next dot is Q3, or Quartile3. The 75% values of data set are within 6 and 27.

The last dot is maximum value of data set, 36 in our box and whisker plot.

So, 75% of the data falls below 27.

Answer: 27 Option(d)

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Answer:

n((2n+3)(5n+2x))

Step-by-step explanation:

that is the step by step solution

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djverab [1.8K]

Answer:

a) f(2) = 4

b) g(3) = 3

c) g(1/3) = -1

d) f(3) = 1/2

e) g(-2) = 2

f) f(π) = 3

Step-by-step explanation:

We are given:

f={(2,4),(-4,3),(3,1/2),(π,3)} and g={(3,3),(-2,2),(1/3,-1)}

We need to find the following values of f and g

a) f(2)

f(2) means when x=2, we need to find the value of y.

Looking at the given f={(2,4),(-4,3),(3,1/2),(π,3)} , when x =2 then y=4

So, f(2) = 4

b) g(3)

g(3) means when x=3, we need to find the value of y.

Looking at the given g={(3,3),(-2,2),(1/3,-1)}, when x =3 then y=3

So, g(3) = 3

c) g(1/3)

g(1/3) means when x=1/3, we need to find the value of y.

Looking at the given g={(3,3),(-2,2),(1/3,-1)}, when x =1/3 then y=-1

So, g(3) = -1

d) f(3)

f(3) means when x=3, we need to find the value of y.

Looking at the given f={(2,4),(-4,3),(3,1/2),(π,3)} , when x =3 then y=1/2

So, f(3) = 1/2

e) g(-2)

g(-2) means when x=-2, we need to find the value of y.

Looking at the given g={(3,3),(-2,2),(1/3,-1)}, when x =-2 then y=2

So, g(-2) = 2

f) f(π)

f(π) means when x=π, we need to find the value of y.

Looking at the given f={(2,4),(-4,3),(3,1/2),(π,3)} , when x =π then y=3

So, f(π) = 3

6 0

3 years ago

–2x + 2y = -4<br> 3х + Зу = -18

rodikova [14]

Answer:

(-2, -4)

Step-by-step explanation:

–2x + 2y = -4

3х + Зу = -18

Divide the first equation by 2

–2x/2 + 2y/2 = -4/2

-x +y = -2

Divide the second equation by 3

3х/3 + Зу/3 = -18/3

x + y = -6

Add these equation together

-x +y = -2

x + y = -6

-------------------

0x + 2y = -8

2y = -8

Divide each side by 2

2y/2 = -8/2

y = -4

Now we need x

x+y = -6

x-4 = -6

Add 4 to each side

x-4+4 = -6+4

x = -2

3 0

3 years ago

Find the length of each side of the triangle determined by the three points P1,P2, and P3. State whether the triangle is an isos

Tanya [424]

Answer:

The triangle is both an Isosceles triangle and a right triangle.

Step-by-step explanation:

Given the vertices of a triangle.

$P_{1} = (- 1, 4)$

$P_{2} = (6, 2)$ and

$P_{3} = (4, - 5)$

We find the distance between all the points to determine the length of each side of the triangle.

Distance between any two points, say, $(x_1, y_1)$ and $(x_2, y_2)$ is:

$\sqrt{\bigg ( \textbf{x}_{\textbf{2}} \hspace{1mm} \textbf{- x}_{\textbf{1}} \bigg )^{\textbf{2}} \textbf{+} \bigg( \textbf{y}_{\textbf{2}} \hspace{1mm} \textbf{- y}_{\textbf{1}} \bigg)^ {\textbf{2}}$

Length between $P_1$ and $P_{2}$ , (Side 1) :

$(x_1, y_1) = (- 1, 4)$ and

$(x_2, y_2) = (6, 2)$

Distance = $\sqrt{\bigg(6 - (-1) \bigg)^{2} \hspace{1mm} + \hspace{1mm} \bigg( 2 - 4 \bigg )^2$

$= \sqrt{7^2 + 2^2}$

$= \sqrt{49 + 4}$

$= \sqrt{\textbf{53}}$

Length of Side 1 = $\sqrt{\textbf{53}}$ units.

Distance between $P_1$ and $P_2$ , (Side 2):

$(x_1, y_1) = (-1, 4)$

$(x_2, y_2) = (4, - 5)$

Distance = $\sqrt{ \bigg( 4 + 1 \bigg)^2 \hspace{1mm} + \bigg( - 5 - 4 \bigg ) ^2$

$= \sqrt{ 25 + 81 }$

$= \sqrt{\textbf{106}}$

Length of Side 2 = $\sqrt{\textbf{106}}$ units.

Distance between $P_2$ and $P_3$ , Side 3 :

$(x_1, y_1) = (4, 5)$

$(x_2, y_2) = (6, 2)$

Distance = $\sqrt{ 2^2 \hspace{1mm} + \hspace{1mm} 7^2}$

$= \sqrt{49 + 4}$

$= \sqrt{\textbf{53}$

Length of Side 3 = $\sqrt{\textbf{53}}$ units.

Note that the length of Side 1 = Length of Side 3.

That means the triangle is Isosceles.

Also, For a triangle to be right angle triangle, using Pythagoras theorem we have:

(Side 1)² + (Side 3)² = (Side 2)²

$\bigg( \sqrt{53} \bigg )^2 \hspace{1mm} + \hspace{1mm} \bigg( \sqrt{53} \bigg)^2 \hspace{1mm} = \hspace{1mm} \bigg ( \sqrt{106} \bigg ) ^2$

i.e, 53 + 53 = 106

Hence, the triangle is a right - angled triangle as well.

7 0

3 years ago