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il63 [147K]
3 years ago
9

What volume is occupied by 35.2 g of carbon tetrachloride if its density is 1.60 g/ml?

Chemistry
2 answers:
ycow [4]3 years ago
8 0

Density is mass divided by volume. Therefore, volume is mass divided by density.

V=\frac{m}{\rho}=\frac{35.2g}{1.60\frac{g}{ml}}=22.0\ ml

shutvik [7]3 years ago
7 0

Answer : The volume of carbon tetrachloride is 22.0 mL

Explanation :

Density : It is defined as the mass contained per unit volume.

Formula used for density :

Density=\frac{Mass}{Volume}

Given :

Mass of carbon tetrachloride = 35.2 grams

Density of carbon tetrachloride = 1.60 g/mL

Now put all the given values in the above formula, we get the volume of carbon tetrachloride.

1.60g/mL=\frac{35.2g}{Volume}

Volume=\frac{35.2g}{1.60g/mL}

Volume=22.0mL

Therefore, the volume of carbon tetrachloride is 22.0 mL

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All of the following are reasons why astronomers have difficulty looking at distant stars except:
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B. They don't understand how red shift affects stars.

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3 years ago
Three Stoichiometry Questions
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Answer:

Explanation:

7)

Given data:

Mass of aluminium = 2.5 g

Mass of oxygen = 2.5 g

Mass of aluminium oxide = 3.5 g

Percent yield = ?

Solution:

Chemical equation:

4Al + 3O₂   →   2Al₂O₃

Number of moles of Al:

Number of moles = mass/ molar mass

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Number of moles of oxygen:

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Now we will compare the moles of aluminium oxide with aluminium and oxygen.

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                           4         :        2

                        0.09      :       2/4×0.09 = 0.045

                          O₂       :        Al₂O₃

                          3         :          2

                         0.08    :        2/3 ×0.08 = 0.053

The number of moles of aluminium oxide produced by Al are less so it will limiting reactant.

Mass of aluminium oxide:

Mass = number of moles × molar mass

Mass = 0.045  × 101.96 g/mol

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Percent yield:

Percent yield = actual yield / theoretical yield ×100

Percent yield = 3.5 g / 4.6 ×100

Percent yield = 76.1%

8)

Given data:

Mass of copper produced = 3.47 g

Mass of aluminium = 1.87 g

Percent yield = ?

Solution:

Chemical equation:

2Al + 3CuSO₄   →   Al₂(SO₄)₃ + 3Cu

Number of moles of Al:

Number of moles = mass/ molar mass

Number of moles = 1.87 g/ 27 g/mol

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Now we will compare the moles of copper with aluminium.

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                           2         :        3

                        0.07      :       3/2×0.09 = 0.105

             

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Mass = number of moles × molar mass

Mass = 0.105  × 63.55 g/mol

Mass = 6.67 g

Percent yield:

Percent yield = actual yield / theoretical yield ×100

Percent yield =  3.47 g / 6.67 × 100

Percent yield = 52%

                       

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