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Roman55 [17]
3 years ago
8

Describe how the potential energy changes

Physics
2 answers:
eimsori [14]3 years ago
6 0
By Moving it

hope this helps
Anarel [89]3 years ago
5 0
To summarize, potential energy<span> is the </span>energy<span> that is stored in an object due to its position relative to some zero position. An object possesses gravitational </span>potential energy<span> if it is positioned at a height above the zero height.</span>
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How much force is required to accelerate a 2 kg mass at 3 m/s2
swat32

Force = (mass) x (acceleration)                  Newton's second law of motion.

Force = (2 kg) x (3 m/s²)  =  6 newtons.

3 0
3 years ago
What type of mirror can produce both<br> converging and diverging rays?
Ivahew [28]

Answer:

A convex mirror is a diverging mirror (f is negative) and forms only one type of image. It is a case 3 image—one that is upright and smaller than the object, just as for diverging lenses.

Explanation:

hope this helps have a good night :)

4 0
2 years ago
Read 2 more answers
A nonconducting sphere has radius R = 1.29 cm and uniformly distributed charge q = +3.83 fC. Take the electric potential at the
zalisa [80]

Answer:

a) -2.516 × 10⁻⁴ V

b) -1.33 × 10⁻³ V

Explanation:

The electric field inside the sphere can be expressed as:

E= \frac{kqr}{R^3}

The potential at a distance can be represented as:

V(r) - V(0) = -\int\limits^r_0 {\frac{kqr}{R^3} } \, dr^2

V(r) - V(0) = [\frac{qr^2}{8 \pi E_0R^3 }]₀

V(r) =   -[\frac{qr^2}{8 \pi E_0R^3 }]₀

Given that:

q = +3.83 fc = 3.83 × 10⁻¹⁵ C

r = 0.56 cm

 = 0.56 × 10⁻² m

R = 1.29 cm

  =  1.29 × 10⁻² m

E₀ = 8.85 × 10⁻¹² F/m

Substituting our values; we have:

V(r) = -\frac{(3.83*10^{-15}C)(0.560*10^{-2}m)^2}{8 \pi (8.85*10^{-12}F/m)(1.29*10^{-2}m)^3}

V(r) = -2.15  × 10⁻⁴ V

The difference between the radial distance  and center can be expressed as:

V(r) - V(0) = -\int\limits^R_0 {\frac{kqr}{R^3} } \, dr^2

V(r) - V(0) =  [\frac{qr^2}{8 \pi E_0R^3 }]^R

V(r) = -\frac{qR^2}{8 \pi E_0R^3 }

V(r) = -\frac{q}{8 \pi E_0R }

V(r) = -\frac{(3.83*10^{-15}C)}{8 \pi (8.85*10^{-12}F/m)(1.29*10^{-2}m)}

V(r) = -0.00133

V(r) = - 1.33 × 10⁻³ V

8 0
2 years ago
A punted football hits the ground with a force of 50 N . According to Newton’s 3rd law of motion what also happens at the same e
Nadya [2.5K]

As per Newton's III law every action has equal and opposite reaction

So here we can say that

every body which apply force on other body must have a reaction force of same magnitude in opposite direction

So here if ball hits the ground by 50 N force then the ball must have a reaction force on itself with same magnitude and opposite direction

the magnitude of the force will be 50 N

and its direction is opposite to the force that ball apply on the floor

4 0
3 years ago
What is the net force on the object in the picture? *<br> F = 30N<br> F<br> = 30N
My name is Ann [436]

Answer:0 N

Explanation:

Because they cancel each other out

7 0
3 years ago
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