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hodyreva [135]
2 years ago
12

When an electron enters a region of uniform magnetic field (B=0.19T), with its

Physics
1 answer:
kobusy [5.1K]2 years ago
3 0

The radius of the track in the circular motion is 0.164 mm.

<h3>Magnetic force of the of charge</h3>

The magnetic force of the charge is calculated as follows;

F = qvB

<h3>Centripetal force of the charge</h3>

The centripetal force experienced by the charge is calculated as follows;

F = \frac{mv^2}{r}

<h3>The magnetic force is equal to the centripetal force</h3>

qvB = \frac{mv^2}{r} \\\\qB = \frac{mv}{r} \\\\r = \frac{mv}{qB} \\\\

<h3>The radius of the track</h3>

The radius of the track is calculated as follows;

r = \frac{9.1 \times 10^{-31} \times 5.5 \times 10^6}{1.6 \times 10^{-19} \times 0.19} \\\\r = 1.64 \times 10^{-4} \ m\\\\r = 0.164 \times 10^{-3} \ m\\\\r = 0.164 \ mm

Thus, the radius of the track in the circular motion is 0.164 mm.

Learn more about magnetic force here: brainly.com/question/13277365

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