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____ [38]
3 years ago
11

A fragment of a collapsing gas cloud that comes to equilibrium with a central temperature of 4 million k will become a:

Physics
1 answer:
Liono4ka [1.6K]3 years ago
4 0
If there's enough Hydrogen in the cloud, then fusion reactions
will ignite in the core, and it'll become a star.
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What is the definition of
marysya [2.9K]
Upper fixed point is a temperature of stem from water boiling and standards atmospheric pressure

Lower fixed point is the temperature of pure melting ice.
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3 years ago
An adult elephant has a mass of about 5.0 tons. An adult elephant shrew has a mass of about 50 grams. How far r from the center
Diano4ka-milaya [45]

Answer:

2023857702.507m

Explanation:

f=\frac{GMm}{r^{2} }

recall from newton's law of gravitation

G=gravitational constant

mshew=50g

melephant=5*10^3kg

rearth=radius of the earth 6400km or 6400000m

mearth= masss of the earth

Gm(shrew)m(earth)/r(earth)^2 = Gm(elephant)m(earth)/r^2

strike out the left hand side and right hand side variables

m(shrew)/r(earth)^2 = m(elephant)/r^2

r^2 = m(elephant).r(earth)^2 / m(shrew)       .........make r^2 the subject of the equation

r^2=(5*10^{3} *(6400000)^{2} )/.05

r^2=40960000000000

r=2023857702.507m

4 0
3 years ago
What do you mean by 5meter length​
zimovet [89]

Answer:

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6 0
3 years ago
Read 2 more answers
The sampling rate of an ADC is 8.1 kHz. What will be an appropriate cut-off frequency (break frequency) for the anti-aliasing fi
KiRa [710]

Answer:

4000 Hz

Explanation:

An anti-alias filter is usually added in front of the ADC to limit a certain range of input frequencies in order to avoid aliasing. This filter is usually a low pass filter that passes low frequencies but attenuates the high frequencies.

The Nyquist sampling criteria states that the sampling rate should be at least twice the maximum frequency component of the desired signal.

Sampling rate = 2(max input frequency)

From the relation we can find out the cut-off frequency for the anti-aliasing filter.

max input frequency = sampling rate/2

max input frequency = 8100/2 = 4050 Hz

Therefore, 4000 Hz would be an appropriate cut-off frequency for the anti-aliasing filter.

3 0
3 years ago
. A non-uniform positive line charge of length 2 m is put along the x-axis as shown in the figure, where x​0​=1.5 m. The linear
PilotLPTM [1.2K]

Answer:

E = 7.2*10^{10}N/C

Explanation:

The differential electric field dE due to differential charge dQ at distance x from the origin is

dE = k\dfrac{dQ}{x^2}

but since dQ = \lambda dx = 4x^2dx we have

dE = k\dfrac{4x^2dx}{x^2}

dE = 4k\: dx

integrating this from x_0 to x_0+L we get

$E = \int^{x_0+L}_{x_0} {4k} \, dx $

E = 4k[(x_0+L)-x_0]

E =4kL

putting in k = 9*10^9Nm^2/C^2 and L =2m we get

\boxed{E = 7.2*10^{10}N/C.}

5 0
3 years ago
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