When I divided by 6, I got W(moon) = mg(moon) = 10 x 10/6 = 16.7N (the moon's gravity is only 1/6 that of Earth in this case). 100N is equal to W(Earth) = mg(Earth) = 10 x 10. On the moon and the Earth, m = 10 kg.
How can you determine the strength of Earth's gravitational field at the moon?
M = 6 10 24 K g is the mass of the earth, and g = - G M R 2 is the gravitational field of the earth at the point of the moon. The distance between the earth and moon is 84 10 8 meters. field of gravitation.
How do you determine the distance between Earth and the moon where the gravitational field is at its weakest?
You only discover points where the forces from all of the different local bodies are in balance, or equal to each other, because there is no place in the universe where the gravitational field intensity is zero. All bodies, not just the Earth and Moon, must be taken into account in the computation to arrive at these positions.
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Answer:
0.737 m/s²
Explanation:
Given:
v₀ = 0 m/s
v = 8.20 m/s
Δx = 45.6 m
Find: a
v² = v₀² + 2aΔx
(8.20 m/s)² = (0 m/s)² + 2a (45.6 m)
a = 0.737 m/s²
Answer:
Specific heat capacity, c = 468.75 J/Kg°C
Explanation:
Given the following data;
Power = 1.5 kW to Watts = 1.5 * 1000 = 1500 Watts
Time = 5 seconds
Mass = 0.2 kg
Initial temperature = 20°C
Final temperature = 100°C
To find specific heat capacity;
First of all, we would have to determine the energy consumption of the kettle;
Energy = power * time
Energy = 1500 * 5
Energy = 7500 Joules
Next, we would calculate the specific heat capacity of water.
Heat capacity is given by the formula;
Where;
- Q represents the heat capacity or quantity of heat.
- m represents the mass of an object.
- c represents the specific heat capacity of water.
- dt represents the change in temperature.
dt = T2 - T1
dt = 100 - 20
dt = 80°C
Making c the subject of formula, we have;

Substituting into the equation, we have;


<em>Specific heat capacity, c = 468.75 J/Kg°C</em>
The first one is C!
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