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Ivan
3 years ago
9

Convert .00016 to scientific notation

Physics
1 answer:
Sholpan [36]3 years ago
5 0

Answer:

1.6 \,\,\,10^{-4}

Explanation:

Recall that scientific notation involves expressing the number in powers of ten, and using a multiplicative factor whose value is larger than or equal to 1 (one) and strictly smaller than 10 in the form:

a\,\,\,10^n\\with\,\,\,1\leq a

and with n an integer value.

in our case, notice that 0.00016 = 16 / 100000 = 1.6 / 10000

and that denominator can be expressed as: 10^4, and can also be brought to the numerator as a negative power of ten:

1.6 / 10000 = 1.6 / 10^4 = 1.6 * 10^(-4)

\frac{16}{100000} =\frac{1.6}{10000}=\frac{1.6}{10^4}=1.6\,\,\,10^{-4}

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A train travels 90 kilometers in 1 hours, and then 60 kilometers in 3 hours. What is its average speed
Serhud [2]
Average speed = (total distance) / (total time to cover the distance)

                       = (90km + 60km) / (1hr + 3hr)

                       =       (150 km)   /   (4 hr)

                       =          37.5 km/hr      . 
7 0
3 years ago
A motorist makes a trip 180 miles. For the first 90 miles she drives the remaining distance of her speed for the total trip is t
Minchanka [31]

so first your going to use v=Δd/Δt given you the answer 80 i think that's right

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3 years ago
Backpackers often use canisters of white gas to fuel a cooking stove's burner. If one canister contains 1.45 L of white gas, and
lorasvet [3.4K]

Answer: One canister contains 1.03 Kg of fuel,

Explanation:

The density is defined as the relation between the mass and the volume p=\frac{m}{v}

First of all you need to have the same units for volume and density, so:

For the volume,

1.45 L * \frac{1.10*10^{-3}m^{3}  }{1 L} = 1.45 *10^{-3} m^{3}

For the density,

p = 0.710\frac{g}{cm^{3} } *\frac{1cm^{3} }{1*10^{-6}m^{3}  }*\frac{1 Kg}{1*10^{3}g } = 710\frac{Kg}{m^{3} }

From the density equation we have m=p*v, so:

710\frac{Kg}{m^{3} } *1.45*10^{-3} m^{3} = 1.03Kg

4 0
4 years ago
A spring of negligible mass stretches 3.00 cm from its relaxed length when a force of 7.50 N is applied. A 0.500-kg particle res
zhannawk [14.2K]

Answer:

a) 250 N/m

b) 22.4 rad/s , 3.6 Hz , 0.28 sec

c) 0.3125 J

Explanation:

a)

F = force applied on the spring = 7.50 N

x = stretch of the spring from relaxed length when force "F" is applied = 3 cm = 0.03 m

k = spring constant of the spring

Since the force applied causes the spring to stretch

F = k x

7.50 = k (0.03)

k = 250 N/m

b)

m = mass of the particle attached to the spring = 0.500 kg

Angular frequency of motion is given as

w = \sqrt{\frac{k}{m}}

w = \sqrt{\frac{250}{0.5}}

w = 22.4 rad/s

f = frequency

Angular frequency is also given as

w = 2 π f

22.4 = 2 (3.14) f

f  = 3.6 Hz

T = Time period

Time period is given as

T = \frac{1}{f}

T = \frac{1}{3.6}

T = 0.28 sec

c)

A = amplitude of motion = 5 cm = 0.05 m

Total energy of the spring-block system is given as

U = (0.5) k A²

U = (0.5) (250) (0.05)²

U = 0.3125 J

5 0
4 years ago
A 100kg cannon at rest contains a 10kgcannonball. when fired,
slega [8]

Answer:

9 m/s

Explanation:

mass of cannon, M = 100 kg

mass of cannon ball, m = 10 kg

velocity of cannon ball, v = 90 m/s

Let the recoil velocity of cannon is V.

Us ethe conservation of linear momentum, as no external force is acting on the system, so the linear momentum of the system is conserved.

Momentum before the firing = momentum after the firing

M x 0 + m x 0 = M x V + m x v

0 = 100 x V + 10 x 90

V = - 9 m/s

Thus, the recoil velocity of cannon is 9 m/s.

4 0
3 years ago
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