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liubo4ka [24]
3 years ago
5

A crest in a transverse wave corresponds to a in a longitudinal wave

Physics
2 answers:
Lerok [7]3 years ago
7 0

Answer: A crest in a transverse wave corresponds to a Compression in a longitudinal wave.


Explanation:


A transverse wave has crests and troughs. Crest and trough are the points on the wave to which maximum displacement of medium particles in upward and downward direction occurs respectively. The medium particles vibrate perpendicular to the direction of propagation of wave.  

A longitudinal wave has compression and rarefaction. The medium particles vibrate parallel to the direction of propagation of wave. A compression is high density region and rarefaction is a low density region.  

A crest is the point on the transverse wave to which the medium particle rises maximum. Correspondingly, in a longitudinal wave, the medium particles come closer to each other and form a denser region. This is known as compression.  

Katena32 [7]3 years ago
6 0

Compression..............

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A soccer player kicks a soccer ball initially at rest setting it in motion at a velocity of 30 m/s. If the ball has a mass of 0.
Alchen [17]

Answer:

 F= 600 N

Explanation:

Given that

Initial velocity ,u= 0 m/s

Final velocity ,v= 30 m/s

mass ,m = 0.5 kg

time ,t= 0.025 s

The change in the linear momentum is given as

ΔP= m (v - u)

ΔP= 0.5 ( 30 - 0 ) kg.m/s

ΔP= 15 kg.m/s

We know that from second law of Newtons

F=\dfrac{dP}{dt}

F=\dfrac{\Delta P}{t}

Now by putting the values

F=\dfrac{15}{0.025}\ N

F= 600 N

5 0
3 years ago
In physics, why would an equation like y=mx+b be plotted as a straight line rather than as a parabola, as is done in math?
notka56 [123]

Answer:

Explanation:

In Both Physics and Math

y=mx+b is plotted as straight line where

m=slope of line

b=intercept on Y-axis

whereas Equation of parabola is something like this

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or

x^2=4ay

Math is a tool to solve Physics problems so equations are same in math and physics

3 0
3 years ago
A spherical snowball melts at a rate proportional to its surface area. (a) write a differential equation for its volume, v. (use
tresset_1 [31]

Answer:

Explanation:

The rate of change in volume is proportional to the surface area:

dV/dt = kA

Integrating:

V = kAt + C

At t=0, V = s, so:

s = kA(0) + C

C = s

Therefore:

V = kAt + s

6 0
3 years ago
Ballistic data obtained on a firing range show that aerodynamic drag reduces the speed of a .44 magnum revolver bullet from 250
m_a_m_a [10]

Answer:

0.363999909622

Explanation:

F = Force

m = Mass = 15.6 g

C = Drag coefficient

ρ = Density of air = 1.21 kg/m³

A = Surface area = \dfrac{\pi}{4}d^2

v = Terminal velocity = v=210\ m/s

s = Displacement = 150 m

a=\dfrac{v^2-u^2}{2s}

Force is given by

F = ma

F=\dfrac{1}{2}\rho CAv^2\\\Rightarrow ma=\dfrac{1}{2}\rho CAv^2\\\Rightarrow m\dfrac{v^2-u^2}{2s}=\dfrac{1}{2}\rho CAv^2\\\Rightarrow C=2\times m\dfrac{v^2-u^2}{2s}\times\dfrac{1}{\rho Av^2}\\\Rightarrow C=2\times15.6\times 10^{-3}\dfrac{210^2-250^2}{2\times 150}\times\dfrac{1}{1.21\times\dfrac{\pi}{4}\times (11.2\times 10^{-3})^2(210)^2}\\\Rightarrow C=-0.363999909622

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4 0
3 years ago
The kinetic friction force between a 60.0-kg object and a horizontal surface is 50.0 N. If the initial speed of the object is 25
Vikki [24]

Answer:

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Explanation:

From the question,

Work done by the frictional force = Kinetic energy of the object

F×d = 1/2m(v²-u²)..................... Equation 1

Where F = Force of friction, d = distance it slide before coming to rest, m = mass of the object, u = initial speed of the object, v = final speed of the object.

Make d the subject of the equation.

d = 1/2m(v²-u²)/F.................. Equation 2

Given: m = 60.0 kg, v = 0 m/s(coming to rest), u = 25 m/s, F = -50 N.

Note: If is negative because it tends to oppose the motion of the object.

Substitute into equation 2

d = 1/2(60)(0²-25²)/-50

d = 30(-625)/-50

d = -18750/-50

d = 375 m.

Hence the it will slide before coming to rest = 375 m

6 0
3 years ago
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