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liubo4ka [24]
3 years ago
5

A crest in a transverse wave corresponds to a in a longitudinal wave

Physics
2 answers:
Lerok [7]3 years ago
7 0

Answer: A crest in a transverse wave corresponds to a Compression in a longitudinal wave.


Explanation:


A transverse wave has crests and troughs. Crest and trough are the points on the wave to which maximum displacement of medium particles in upward and downward direction occurs respectively. The medium particles vibrate perpendicular to the direction of propagation of wave.  

A longitudinal wave has compression and rarefaction. The medium particles vibrate parallel to the direction of propagation of wave. A compression is high density region and rarefaction is a low density region.  

A crest is the point on the transverse wave to which the medium particle rises maximum. Correspondingly, in a longitudinal wave, the medium particles come closer to each other and form a denser region. This is known as compression.  

Katena32 [7]3 years ago
6 0

Compression..............

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2 years ago
A person, with his ear to the ground, sees a huge stone strike the concrete pavement. A moment later two sounds are heard from t
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Answer:

The impact occured at a distance of 2478.585 meters from the person.

Explanation:

(After some research on web, we conclude that problem is not incomplete) The element "Part A" may lead to the false idea that question is incomplete. Correct form is presented below:

<em>A person, with his ear to the ground, sees a huge stone strike the concrete pavement. A moment later two sounds are heard from the impact: one travels in the air and the other in the concrete, and they are 6.4 seconds apart. How far away did the impact occur? (Sound speed in the air: 343 meters per second, sound speed in concrete: 3000 meters per second)</em>

Sound is a manifestation of mechanical waves, which needs a medium to propagate themselves. Depending on the material, sound will take more or less time to travel a given distance. From statement, we know this time difference between air and concrete (\Delta t), in seconds:

\Delta t = t_{A}-t_{C} (1)

Where:

t_{C} - Time spent by the sound in concrete, in seconds.

t_{A} - Time spent by the sound in the air, in seconds.

By suposing that sound travels the same distance and at constant speed in both materials, we have the following expression:

\Delta t = \frac{x}{v_{A}}-\frac{x}{v_{C}}

\Delta t = x\cdot \left(\frac{1}{v_{A}}-\frac{1}{v_{C}}  \right)

x = \frac{\Delta t}{\frac{1}{v_{A}}-\frac{1}{v_{C}}  } (2)

Where:

v_{C} - Speed of the sound in concrete, in meters per second.

v_{A} - Speed of the sound in the air, in meters per second.

x - Distance traveled by the sound, in meters.

If we know that \Delta t = 6.4\,s, v_{C} = 3000\,\frac{m}{s} and v_{A} = 343\,\frac{m}{s}, then the distance travelled by the sound is:

x = \frac{\Delta t}{\frac{1}{v_{A}}-\frac{1}{v_{C}}  }

x = 2478.585\,m

The impact occured at a distance of 2478.585 meters from the person.

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