<span>The maxima of an equation can be obtained by taking the 1st
derivative of the equation then equate it to 0.</span>The value of N that result in best yield is when dy/dn = 0.
Taking the 1st derivative of
the equation y=(kn)/(9+n^2) :<span>
</span>
By using the quotient
rule the form of the equation is:<span>
y = g(n) / h(n)
where:</span>
g(n) = kn --->
g'(n) = k
<span>
<span>h(n) = 9 + n^2 ---> h'(n) = 2n </span>
dy/dn is defined as:
<span>dy/dn = [h(n) * g'(n) - h'(n) * g(n)] / h(n)^2
dy/dn = [(9 + n^2)(k) - (kn)(2n)] / (9 +
n^2)^2
dy/dn = (9k + kn^2 - 2kn^2) / (9 + n^2)^2
dy/dn = (9k - kn^2) / (9 + n^2)^2
dy/dn = k(9 - n^2) / (9 + n^2)^2
<span>Equate dy/dn = 0, then solve for n
k(9 - n^2) / (9 + n^2)^2 = 0
k(9 - n^2) = 0
9 - n^2 = 0
n^2 = 9
n = sqrt(9)
n = 3
<span>Answer: The nitrogen
level that gives the best yield of agricultural crops is 3 units.</span></span></span></span>
The zebra could be "hen pecked" if the vulture was a hen bird. On the other hand, the two might get along ok. In UK, it they 'd make a useful combination helping each other to cross increasingly dangerous roads (joke).
Second hand:
1 rev per minute = (2π radians/minute) x (1 min/60sec) = π/30 rad/sec
Minute hand:
1 rev per hour = (2π radians/hour) x (1 hr/3600 sec) = π/1800 rad/sec
Hour hand:
1 rev per 12 hours = (2π rad/12 hr) x (1 hr/3600 sec) = π/21,600 rad/sec
As long as the clock is in good working order, and the hands are turning steadily at their normal rate, there is no angular acceleration.
The correct answer is:
<span>C: in the protons and neutrons of an atom
In fact, the nuclear energy refers to the binding energy of the nucleons (protons and neutrons) of an atom. The protons and the neutrons are held together by the strong nuclear interaction, one of the four fundamental forces of nature, and the energy associated to this interaction is called nuclear energy.
</span>
Answer:
Magnetic field strength required for this is 0.25 T
Explanation:
As we know that the proton moves in circular path in uniform magnetic field
so the radius of the path of the circle is given as
here we know that
now we have
so we have
