Answer:
k = 2.647 x 10-2 M-2 s-1
Explanation:
2NO(g) +Cl2(g) --> 2NOCl(g)
Experiment [NO] (M) [Cl2] (M) Rate (M/s)
1 0.0300 0.0100 3.4 x 10-4
2 0.0150 0.0100 8.5 x 10-5
3 0.0150 0.0400 3.4 x 10-4
Frrom experiments 1 and 3;
Reducing the concentration of NO by a factor of 2 decreases the rate of the reaction by a factor of 4. This means the reaction is second order with respect to NO.
From experiments 2 and 3:
Increasing the concentration of Cl2 by a factor of 4 increases the rate by a factor of 4. This means the reaction is first order with respect to Cl2
The rate equation is given as;
Rate = k [NO]² [Cl2]
From experiment 1;
k = [NO]² [Cl2] / Rate
k = 0.0300² * 0.0100 / 3.4 x 10-4
k = 2.647 x 10-2 M-2 s-1
The correct answer is A. electrons can only jump from one energy level to the next and can't go anywhere in between. This makes it so that the amount of energy an electron can absorb and release are quantized which makes it so that they can only put out light that has certain energies.
I hope this helps. Let me know if anything is unclear.
Answer:
0.081g
Explanation:
first step:calculate the molar conc of the stock solution
molar conc=mass/molar mass ×1000/vol(ml)
molar mass of Co(N03)2=182.943
molar conc=3g/182.943 ×1000/100ml
=0.163M
To calculate the conc of the resulting solution we apply the dilution principle
n=cv
C1V1=C2V2
C1=conc of stock solution=0.163M
V1=4mL
V2=275ml(final volume)
by making 'C2" the subject C2=0.163×4/275
=0.0024M
by applying the formular for calculating molar conc of a solution,we can calculate the mass of CO(NO3)2 in the reulting solution
molar conc=mass/molar mass ×1000(L)/vol(mL)
mass=0.0024×182.943×275/1000
=0.1193g
Mass of CO(NO3)2 in the resulting solution=0.1199g
since CO+(NO3)2=CO(NO3)2
Percentage by mass of (NO3)2 in CO(NO3)2=(NO3)2/CO(NO3)2
=124/182.943×100
=67.8%
it means 67.8% of 0.1193g is the mass of (NO3)2=0.678×0.1199
=0.081g