Answer:
C3H6 + Br2 → C3H6Br2
Explanation:
The reaction in which C3H6Br2 (1,2-Dibromopropane) is created is:
We can see that the only difference between the product (C3H6Br2) and the known reactant (C3H6) of the reaction is two bromine atoms (Br2). Br2 is diatomic bromine - a molecule we get after combining two bromine atoms. This compound is a red-brown liquid at room temperature, which means that that is the liquid described in your question.
Answer:
2VO + 3Fe2O3 —> V2O5 + 6FeO
Explanation:
The skeletal equation for the reaction is given below below:
VO + Fe2O3 —> V2O5 + FeO
We can balance the equation above by doing the following:
There are 2 atoms of V on the right side and 1 atom on the left side. It can be balance by putting 2 in front of VO as shown below:
2VO + Fe2O3 —> V2O5 + FeO
Now, we have a total of 5 atoms of O on the left and 6 atoms on the right side. We can balance it by putting 3 in front of Fe2O3 and 6 in front of FeO as shown below:
2VO + 3Fe2O3 —> V2O5 + 6FeO
Now, we can see that the equation is balanced
Answer:
pls the image didn't come
Explanation:
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Answer:
<em> 14, 508J/K</em>
ΔHrxn =q/n
where q = heat absorbed and n = moles
Explanation:
<em>m = mass of substance (g) = 0.1184g</em>
1 mole of Mg - 24g
<em>n</em> moles - 0.1184g
<em>n = 0.0049 moles.</em>
Also, q = m × c × ΔT
<em> Heat Capacity, C of MgCl2 = 71.09 J/(mol K)</em>
<em>∴ specific heat c of MgCL2 = 71.09/0.0049 (from the formula c = C/n)</em>
<em>= 14, 508 J/K/kg</em>
ΔT= (final - initial) temp = 38.3 - 27.2
= 11.1 °C.
mass of MgCl2 = 95.211 × 0.1184 = 11.27
⇒ q = 11.27g × 11.1 °C × <em>14, 508 j/K/kg </em>
<em>= 1,7117.7472 J °C-1 g-1</em>
<em />
<em>∴ ΔHrxn = q/n</em>
<em>=1,7117.7472 ÷ 0.1184 </em>
<em>= 14, 508J/K</em>
