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kodGreya [7K]
3 years ago
14

The passage below describes an experiment. Read the passage and then follow the instructions below.

Chemistry
2 answers:
mafiozo [28]3 years ago
4 0

Answer:

75% + 60°F + 80°F + 60.

Explanation:

Since I got it wrong, try this one.

hope this helps.

(Answer is 275).

Tresset [83]3 years ago
3 0

Answer:

75 + 60 + 80 +60

Explanation:

In grade 7 you will learn how to get all templates

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Write a balanced half-reaction for the reduction of bismuth oxide ion to bismuth ion in basic aqueous solution. Be sure to add p
Butoxors [25]

Answer:

3H_2O+(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+6OH^-

Explanation:

Hello there!

In this case, according to the required half-reaction, we start by setting it up from bismuth (V) oxide ion to bismuth (III) ion:

BiO_3^-\rightarrow Bi^{3+}

Thus, next realize that the oxidation state of Bi in BiO3^- is 5+ because oxygen is 2- (-2*3+x=-1;x=-1+6;x=+5), so we obtain:

(Bi^{5+}O_3)^-\rightarrow Bi^{3+}

Thereafter, we realize three water molecules are needed on the right in order to balance the oxygens and consequently 6 hydrogen atoms on the left to balance hydrogen:

6H^++(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+3H_2O

Now, since the balance is is basic media, we add six molecules of hydroxide ions in order to produce water with the hydrogen ones:

6OH^-+6H^++(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+3H_2O+6OH^-\\\\6H_2O+(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+3H_2O+6OH^-\\\\6H_2O-3H_2O+(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+6OH^-

Then, we accommodate the waters to obtain:

3H_2O+(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+6OH^-

Best regards!

7 0
3 years ago
A. In the complete reaction of 22.99 g of sodium
fenix001 [56]

Answer : 58.44 g

<h3>Further explanation</h3>

The reaction

\tt Na+Cl\Rightarrow NaCl

mole ratio :

Na : Cl : NaCl = 1 : 1 : 1

Molar mass of Na : 22,989769 g/mol = 22.99 g/mol

Molar mass of Cl : 35,453 g/mol= 35.45 g/mol

Molar mass of NaCl : 58,44 g/mol

Let's check the mol for reactant (Na and Cl) and product(NaCl)

  • mol of Na :

\tt mol=\dfrac{22.99}{22.99}=1

  • mol of Cl :

\tt mol=\dfrac{35.45}{35.45}=1

Then the reactants are completed reacting because it matches the mole ratio, which is 1: 1

so that the mole of the product can be determined from the mol Na or Cl, which is 1

  • mass of NaCl :

\tt =\dfrac{mol~NaCl}{mol~Na}\times MW~NaCl\\\\=\dfrac{1}{1}\times 58.44\\\\=\boxed{\bold{58.44~g}}

3 0
4 years ago
At STP, which substance has metallic bonding?
kogti [31]
Silver has metallic bonding.

Silver is a very typical and main metal. The negatively charged electrons distribute themselves throughout the entire piece of metal and form non directional bonds between the positive silver ions, which is metallic bonding, and what silver contributes.
7 0
4 years ago
Read 2 more answers
The acid dissociation constant, Ka, of HNO3 is 4.0 x104. What does the ka
Shtirlitz [24]

Answer:

i thing its b

Explanation:

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3 years ago
What is an electrolitic cell​
stira [4]

A electrolytic* cell that electrolysis occurs

Ex. let say you wanted traces of graphene you would set up your usual electro-chemical exfoliation rig and the graphite you submerge would be your electrolytic cell.

Hopped this helped

6 0
3 years ago
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