8x²+3y²=24
8x²+3y²-24=0
Let x be 1 ,
Therefore
8+3y²-24=0
3y²-16=0
3y²=16
y²=16/3
y=4/1.7
y=40/17
<em><u>Take</u></em><em><u> </u></em><em><u>different</u></em><em><u> </u></em><em><u>values</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>x</u></em><em><u> </u></em><em><u>&</u></em><em><u>y</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>plot</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>graph</u></em><em><u>!</u></em><em><u>!</u></em><em><u>!</u></em>
Y - 5 = -1/2(x-1)
hope this helps!
The probability is low.
20% of 9 is 2. Therefore, the probability is low that 5 out of the 9 students drive cars.
Note: Consider "÷" sign instead of "=".
Given:

To find:
The quotient.
Solution:
We have,

It can be written as

Splitting the middle terms, we get


Taking out the common factor (x-1), we get

Cancel the common factors.

The quotient is
.
Therefore, the correct option is D.
Answer:
277,200
Step-by-step explanation:
To find the number of permutation we can form from the letters of the word "engineering", we first need to find the frequencies of the different letters present.
E = 3
G = 2
N= 3
I = 2
R = 1
Now that we have the frequencies, we count the number of letters in the word "engineering".
E N G I N E E R I N G
11 letters
Now we take the factorial of total number of letters and divide it by the number of repeats and their factorial
So we get:

We remove the 1! because it will just yield 1.

So the total number of permutations from the letters of the word "engineering" will be:
Total number of permutations = 
Total number of permutations = 277,200