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Nataly_w [17]
2 years ago
12

Please help fast! I need the answer along with step by steps explaining to I can learn it thanks I’ll give brainlist to who does

it for me I appreciate it!

Mathematics
1 answer:
Nuetrik [128]2 years ago
3 0

Answer:

?

Step-by-step explanation:

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katen-ka-za [31]

8x²+3y²=24

8x²+3y²-24=0

Let x be 1 ,

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8+3y²-24=0

3y²-16=0

3y²=16

y²=16/3

y=4/1.7

y=40/17

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3 years ago
SOMEONE HELP ME PLEASE
Novay_Z [31]
Y - 5 = -1/2(x-1)

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3 0
2 years ago
20% of students drive a car. 9 students are randomly are selected and asked if they drive a car. What is the probability that ex
Andre45 [30]

The probability is low.

20% of 9 is 2. Therefore, the probability is low that 5 out of the 9 students drive cars.

6 0
2 years ago
What is the quotient of (x3 - 3x2 + 5x – 3) = (x - 1)?
IRINA_888 [86]

Note: Consider "÷" sign instead of "=".

Given:

(x^3-3x^2+5x-3)\div (x-1)

To find:

The quotient.

Solution:

We have,

(x^3-3x^2+5x-3)\div (x-1)

It can be written as

=\dfrac{x^3-3x^2+5x-3}{x-1}

Splitting the middle terms, we get

=\dfrac{x^3-x^2-2x^2+2x+3x-3}{x-1}

=\dfrac{x^2(x-1)-2x(x-1)+3(x-1)}{x-1}

Taking out the common factor (x-1), we get

=\dfrac{(x-1)(x^2-2x+3)}{x-1}

Cancel the common factors.

=x^2-2x+3

The quotient is x^2-2x+3.

Therefore, the correct option is D.

7 0
2 years ago
Read 2 more answers
How many permutations can be formed from all the letters in the word engineering?
laila [671]

Answer:

277,200

Step-by-step explanation:

To find the number of permutation we can form from the letters of the word "engineering", we first need to find the frequencies of the different letters present.

E = 3

G = 2

N= 3

I = 2

R = 1

Now that we have the frequencies, we count the number of letters in the word "engineering".

E N G I N E E R I N G

11 letters

Now we take the factorial of total number of letters and divide it by the number of repeats and their factorial

So we get:

\dfrac{11!}{3!2!3!2!1!}

We remove the 1! because it will just yield 1.

\dfrac{11!}{3!2!3!2!}

So the total number of permutations from the letters of the word "engineering" will be:

Total number of permutations = \dfrac{39,916,800}{144}

Total number of permutations = 277,200

3 0
3 years ago
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