Answer:
when an acount is made online i can also give you the other awnsers
Explanation:
Answer: 24.5 cm
Explanation:
Given
Force constant of spring, k = 40 N/m
Diameter of spring, d = 5.1 cm = 0.051 m
Mass of cylinder, m = 1.5 kg
Let us assume that the cylinder is hanging in such a way that the circular end is parallel with the water. Also, we assume that the tank water level is not materially affected by the displacement of the cylinder while the cylinder sinks. The water is fresh and as we all know, the density of water is 1000 kg/m³
To solve this, we assume x to be the spring extension and it's equivalent sinking distance(in meters). We then apply the formula,
mg = kx + ρgAx
mg = x(k + ρgA)
x = mg / (k + ρgA), where
A = πd²/4
A = (3.142 * 0.051²)/4
A = 0.0082 / 4
A = 0.00205 m²
x = 1.5 * 9.81 / [40 + (1000 * 9.81 * 0.00205)]
x = 14.715 / (40 + 20.1105)
x = 14.715 / 60.1105
x = 0.245 m
or 24.5 cm of stretch or sinking
Answer:
x = 27.3 m
Explanation:
This is a projectile launching exercise, let's start by looking for the time it takes for the rock to reach the height of the window.
Let's use trigonometry to find the velocities of the rock
sin 40 = / v
cos 40 = v₀ₓ / v
v_{oy}= v sin 40
v₀ₓ = v cos 40
v_{oy} = 30 sin 40 = 19.28 m / s
v₀ₓ = v cos 40
v₀ₓ = 30 cos 40 = 22.98 m / s
we look for the time
= v_{oy}^2 - 2 g y
v_{y}^2 = 19.28 2 - 2 9.8 16 = 371.71 - 313.6 = 58.118
v_{y} = 7.623 m / s
we calculate the time
v_{y} = v_{oy} - gt
t = (v_{oy} - v_{y}) / g
t = (19.28 -7.623) / 9.8
t = 1,189 s
since the time is the same for both movements let's use this time to find the horizontal distance
x = v₀ₓ t
x = 22.98 1,189
x = 27.3 m
Answer:
Hey
Your answer would be
The moon is not visible
due to Earth's shadow=lunar eclipse
The sun is not visible due
to the moon=solar eclipse
The moon is on the side of
Earth opposite the sun=new moon
The moon and sun are on
the same side of Earth=full mon