2. Determine the units of the quantity described by each of the following

A dune buggy moves through the hallway at 61.5 cm/s. How far does it travel in 4 minutes?

Contact [7]

Answer:

480.32 foot per second

Explanation:

there is a conversion thing ona famous search engine use that and I just multiple by 4

8 0

3 years ago

You drop a rock into a pond, and water waves spread out in circles. (a) The waves carry water outward, away from where the rock

coldgirl [10]

Answer:

Explanation:

wave motion is defined as the propagation of the disturbance due to continous vibration of the molecules of the medium. Waves oduced due to disturbance carry only energy but not the matter.

The waves move water up and down and carry the energy.

Therefoe, the statement "(a) The waves carry water outward away from where the rock hit. The moving water carries energy outward"is incorrect.

The waves move water up and down and carry the energy, but not matter.

Therefore, the statement "(c) The waves ony make the water move u and down. No energy is carried outward from where the rock hit" is incorrect.

When a rock is droed ito a pd, a disturbance starts from the point where the stone hits the water. The waves produced carry the energy from the starting point toother locatons over a large distance which is not possible by the single molecules of water.

Therefore, the statement "(c) The waves only make the water move up and down, but the waves do carry energy outward away from where the rock hit" is correct.

4 0

3 years ago

If the gradient of an Extension versus Force graph was found to be 5.6, then what is the value of the spring constant? *

worty [1.4K]

Answer:

5.6

Explanation:

F=kx is the formula for spring force. If Extension versus Force was graphed, a linear relation would appear, where the slope is the k value, aka the spring constant.

5 0

3 years ago

vehicles equipped with disc brakes incorporate a mechanically operated drum-style parking brake in the center of the rear disc b

umka21 [38]

Vehicles equipped with disc brakes incorporate a mechanically operated drum-style parking brake in the center of the rear disc brake rotors, commonly called a top hat parking brake.

<h3>What is top hat parking brake?</h3>

The top hat drum style of parking brake system is called the top hat rotors because of how big the middle part is compared to regular rotors.

In this type of parking brake system, the vehicle is equipped with disc brakes which incorporate a mechanically operated drum-style parking brake in the center of the rear disc brake rotors.

Thus, vehicles equipped with disc brakes incorporate a mechanically operated drum-style parking brake in the center of the rear disc brake rotors, commonly called a top hat parking brake.

Learn more about top hat parking brake here: brainly.com/question/21854030

4 0

2 years ago

A seagull flying horizontally over the ocean at a constant speed of 2.60 m/s carries a small fish in its mouth. It accidentally

Ivenika [448]

(a) +2.60 m/s

The motion of the fish dropped by the seagul is a projectile motion, which consists of two independent motions:

- a horizontal uniform motion, at constant speed

- a vertical motion, at constant acceleration (acceleration of gravity, $g=-9.8 m/s^2$ , downward)

In this part we are only interested in the horizontal motion. As we said the horizontal component of the fish's velocity does not change, therefore its value when the fish reaches the ocean is equal to its initial value, which is the speed at which the seagull was flying (because it was flying horizontally):

$v_x = +2.60 m/s$

(b) -17.2 m/s

The vertical component of the fish's velocity instead follows the equation:

$v_y = u_y +gt$

where

$u_y = 0$ is the initial vertical velocity, which is zero

$g=-9.8 m/s^2$ is the acceleration of gravity

t is the time

Since the fish reaches the ocean at t = 1.75 s, we can substitute this time into the formula to find the final vertical velocity:

$v_y = 0+(-9.8)(1.75)=-17.2 m/s$

where the negative sign indicates the direction (downward).

(c)

The horizontal component of the fish's velocity would increase

The vertical component of the fish's velocity would stay the same.

As we said from part (a) and (b):

- The horizontal component of the fish's velocity is constant during the motion and it is equal to the initial velocity of the seagull -> so if the seagull's initial speed increases, the horizontal velocity of the fish will increase too

- The vertical component of the fish's velocity does not depend on the original speed of the seagull, therefore it is not affected.

4 0

3 years ago