Answer:
6
Step-by-step explanation:
the rest are boys
Area of a rectangle=length x width
You have two rectangles:
First rectangle (the biggest):
length=9 yd
width=12 yd-6 yd=6 yd
Area of the biggest rectangle=(9 yd)(6 yd)=54 yd²
Second rectangle (the smallest)
length=6 yd
width=3 yd
Area of the smallest rectangle=(6 yd)(3 yd)=18 yd²
Area of the ballroom=area of the biggest rectangle + area of the smallest rectangle.
area of the ballroom=54 yd² +18 yd²=72 yd²
Answer:
Step-by-step explanation:
Given:
Solving for 
:
Answer:
Step-by-step explanation:
let : x the length and y the width .... ( x > y and x ; y reals numbers )
the perimeter is : 2(x+y)
2(x+y) = 55...(1)
x/y = 7/4 ...(2)
by (2) : x = (7/4)y
subsct in (1) : 2( (7/4)y +y ) =55
(7/2)y +2y =55
multiply by 2
7y +4y = 110
11y = 110
y = 10
x = (7/4)(10)
x = 35/2
Let the numbers be x&y
X+y=109
Taking a as the smallest number we multiply by 4
So according to the question you will have this equation
Y(as the largest number) -4x=4. Y-4x=4
Then find y
Y=4x+4
Substitute y on the first equation to get a
X+y=109
X+4x+4=109
X=21
21+y=109
Y=88
HOPE IT HELPS PLS MARK AS BRAINLIEST
