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Stels [109]
3 years ago
13

Typically during thunderstorms most lightning strikes carry a negative electric charge; only a few carry a positive charge. Thun

derstorms with unusually high proportions of positive-charge strikes tend to occur in smoky areas near forest fires. The fact that smoke carries positively charged smoke particles into the air above a fire suggests the hypothesis that the extra positive strikes occur because of the presence of such particles in the storm clouds. Which of the following, if discovered to be true, most seriously undermines the hypothesis?
(A) Other kinds of rare lightning also occur with unusually high frequency in the vicinity of forest fires.
(B) The positive-charge strikes that occur near forest fires tend to be no more powerful than positive strikes normally are.
(C) A positive-charge strike is as likely to start a forest fire as a negative charge strike is.
(D) Thunderstorms that occur in drifting clouds of smoke have extra positive-charge strikes weeks after the charge of the smoke particles has dissipated.
(E) The total number of lightning strikes during a thunderstorm is usually within the normal range in the vicinity of a forest fire.
Physics
1 answer:
Ierofanga [76]3 years ago
7 0

Answer:<em> Option (D) is correct.</em>

Explanation:

Considering the hypothesis elaborated in this comprehension, it's given that areas that tend to lie near forest fires usually have extra positive strikes since smoke carries positively charged particles. In rudimentary term, this states that occurrence of positively charged particles will result in extra positive strikes.

Option (D) states that occurrence of extra positive strikes will be there even weeks after the charge of smoke particles have been dissociated.

Therefore this option, most seriously undermines the hypothesis.

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Fighter jet starting from airbase A flies 300 km east , then 350 km at 30° west of north and then 150km north to arrive finally
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A jet fighter flies from the airbase A 300 km East to the point M. Then 350 km at 30° West of North.
It means : at 60° North of West. So the distance from the final point to the line AM is :
350 · cos 60° = 350 · 0.866 = 303.1 km
Let`s assume that there is a line N on AM.
AN = 125 km and NM = 175 km.
And finally jet fighter flies 150 km North to arrive at airbase B.
NB = 303.1 + 150 = 453.1 km
Then we can use the Pythagorean theorem.
d ( AB ) = √(453.1² + 125²) = √(205,299.61 + 15,625) = 470 km
Also foe a direction: cos α = 125 / 470 = 0.266
α = cos^(-1) 0.266 = 74.6°
90° - 74.6° = 15.4°
Answer: The distance between the airbase A and B is 470 km.
Direction is : 15.4° East from the North. 
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