A ball is thrown with an initial speed of 20m/s at an angle of 60 to the ground. If air resistance is negligible, what is the ba
ll ‘s speed at the instant it reaches its maximum height from the ground.
1 answer:
Answer:
when a ball is thrown to the air and it attains it maximum height it's value is 0.
Explanation:
Therefore
V = Ucos angle
V = 20 cos 60°
V = 20 x0. 5
V= 10m/s
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Newton’s Second Law concerns the generation of force based on an object’s mass and acceleration, as described by the equation F=ma.
Hope this helps!
Answer:
A. 4.67 m/s²
Explanation:
u = 145 m/s
v = 75 m/s
t = 15 s
a = v - u / t
= 145 - 75 / 15
= 4.67 m/s²
Hope this helped...
Uhh? Do you have any questions or need help?
Let F1=Force exerted by the brother (+F1)
F1= Force exerted by the sister (-F2)
Fnet=(+F1) + (-F2)
Fnet= (+F1) + (-F2)
Fnet=F1 - F2
Fnet= (+3N)+(-5N)
Fnet= -2N
-F
towards the sister (-F) (greater force applied)
depends on the speed limit
