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Firdavs [7]
3 years ago
11

What is the primary consideration in choosing a solvent for crystallizing a compound

Physics
1 answer:
Nina [5.8K]3 years ago
6 0

Answer:

1. The compound should be dissolved at the solvent boiling point.

2. It should be better none of the compound dissolve while at room

   temperature.

3. The compound must have lower boiling point (low boiling point) than

    melting point in hot solvent so to avoid it melts.

4. The compound have different solubility and impurity.

Explanation:

in order a compound to have a good crystallization, these are the primary consideration that should be followed.

1. The compound should be dissolved at the solvent boiling point.

2. It should be better none of the compound dissolve while at room

   temperature.

3. The compound must have lower boiling point (low boiling point) than

    melting point in hot solvent so to avoid it melts.

4. The compound have different solubility and impurity.

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A tightly wound 1000-turn toroid has an inner radius 1.00 cm and an outer radius 2.00 cm, and carries a current of 1.50 A. The t
V125BC [204]

Therefore, the magnitude of magnetic field at a distance 1.10cm from the origin is 27.3mT

<u>Explanation:</u>

Given;

Number of turns, N = 1000

Inner radius, r₁ = 1cm

Outer radius, r₂ = 2cm

Current, I = 1.5A

Magnetic field strength, B = ?

The magnetic field inside a tightly wound toroid is given by B = μ₀ NI / 2πr

where,

a < r < b and a and b are the inner and outer radii of the toroid.

The magnetic field of toroid is

B = \frac{u_oNI}{2\pi r}

Substituting the values in the formula:

B (1.10cm) = \frac{(4\pi X 10^-^7 ) ( 1000)(1.5)}{2\pi (1.10) } \\\\

B (1.10cm) = 27.3mT

Therefore, the magnitude of magnetic field at a distance 1.10cm from the origin is 27.3mT

7 0
3 years ago
Un observador se halla a 510m. de una pared. entre el observador y la pared, y a igual distancia de ambos, se realiza un disparo
ch4aika [34]

Answer:

a)    t = 0.75 s,  b)  t = 2.25 s

Explanation:

The speed of sound is constant in a material medium

           v = 340 m / s

we can use the relations of uniform motion to find the time

          v = x / t

          t = x / v

In the exercise, the observer's distance to the wall is indicated d = 510 m, it also indicates that the shot is fired at the midpoint

          x = d / 2

       

a) direct sound the distance from the observer to the screen is

           x = 510/2 = 255 m

           t = 255/340

           t = 0.75 s

b) echo sound.

In this case the sound reaches the wall bounces, the distance is

             x = d / 2 + d

             x = 3/2 d

             x = 3/2 510

             x = 765 m

the time is

              t = x / v

              t = 765/340

              t = 2.25 s

5 0
3 years ago
an 1800-w toaster, a 1400-w electric frying pan, and a 75-w lamp are plugged into the same outlet in a 15-a, 120-v circuit. (the
Gnom [1K]

The current drawn by the electric frying pan is <u>27.295 A.</u>

<u />

Power of toaster, P1 = 1800 W

Power of electric frying pan, P2 = 1400 W

Power of lamp, P3 = 75 W

Three devices are in parallel combination. So their Voltage difference is the same.

∆V = 120 Volt

Current is drawn by frying pan, I1 = P1/∆V = 1800/120 = 15 A

Current drawn by an electric frying pan, I2= 1400/120 = 11.67 A

Current drawn by frying pan, I3 = P3/120 = 75/120 = 0.625 A

Total current frying pan= (15 + 11.67 + 0.625) = 27.295 A

Electric current refers to the float of electricity in an electronic circuit, and to the amount of strength flowing via a circuit. it is measured in amperes (A). the bigger the price in amperes, the greater electricity is flowing inside the circuit.

The current is the charge of glide of price across a cross-segment every day to the direction of the float of the current. The S.I. unit of modern is coulomb consistent with 2d which is called ampere and denoted by means of A.

Learn more about current here:-brainly.com/question/24858512

#SPJ4

8 0
2 years ago
A cylinder of radius r=10.0 cm and height h=20.0 cm
Olenka [21]
D I think is the correct answer
If the cylinder is slightly
7 0
2 years ago
There is a potential difference of 1.1 V between the ends of a 10 cm long graphite rod that has a cross-sectional area of 0.90 m
Serga [27]

Explanation:

It is given that,

Potential difference between the ends of a rod, V = 1.1 V

Length of the rod, l = 10 cm = 0.1 m

Area of cross section of the rod, A=0.9\ mm^2=9\times 10^{-7}\ m^2

The resistivity of graphite, \rho=7.5\times 10^{-6}\ \Omega-m

(a) Let R is the resistance of the rod. It is given by :

R=\rho \dfrac{l}{A}

R=7.5\times 10^{-6}\times \dfrac{0.1}{9\times 10^{-7}}

R=0.833\ \Omega

So, the resistance of the rod is 0.833 ohms.

(b) Let I is the current flowing in the wire. It can be calculated using the Ohm's law as :

I=\dfrac{V}{R}

I=\dfrac{1.1\ V}{0.833\ \Omega}

I = 1.32 A

(c) Let E is the electric field inside the rod. The electric field in terms of potential difference is given by :

E=\dfrac{V}{l}

E=\dfrac{1.1\ V}{0.1\ m}

E = 11 V/m

Hence, this is the required solution.

8 0
3 years ago
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