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3 years ago

What is the primary consideration in choosing a solvent for crystallizing a compound

Physics

1 answer:

Nina [5.8K]3 years ago

6 0

Answer:

1. The compound should be dissolved at the solvent boiling point.

2. It should be better none of the compound dissolve while at room

temperature.

3. The compound must have lower boiling point (low boiling point) than

melting point in hot solvent so to avoid it melts.

4. The compound have different solubility and impurity.

Explanation:

in order a compound to have a good crystallization, these are the primary consideration that should be followed.

1. The compound should be dissolved at the solvent boiling point.

2. It should be better none of the compound dissolve while at room

temperature.

3. The compound must have lower boiling point (low boiling point) than

melting point in hot solvent so to avoid it melts.

4. The compound have different solubility and impurity.

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The toxic effects of water pollution are generally _______.

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<span>Immediate and long lasting because they pollute the water itself which is the most important commodity for humans. Dirty water gives us all types of diseases which are all long lasting and the body has a immediate reaction to the pollutants in the water. Drinking polluted water or even bathing in it can be very harmful to the human body.</span>

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3 years ago

Radar uses radio waves of a wavelength of 2.4 ${\rm m}$ . The time interval for one radiation pulse is 100 times larger than t

blondinia [14]

Answer:

120 m

Explanation:

Given:

wavelength 'λ' = 2.4m

pulse width 'τ'= 100T ('T' is the time of one oscillation)

The below inequality express the range of distances to an object that radar can detect

τc/2 < x < Tc/2 ---->eq(1)

Where, τc/2 is the shortest distance

First we'll calculate Frequency 'f' in order to determine time of one oscillation 'T'

f = c/λ (c= speed of light i.e 3 x $10^{8}$ m/s)

f= 3 x $10^{8}$ / 2.4

f=1.25 x $10^{8}$ hz.

As, T= 1/f

time of one oscillation T= 1/1.25 x $10^{8}$

T= 8 x $10^{-9}$ s

It was given that pulse width 'τ'= 100T

τ= 100 x 8 x $10^{-9}$ => 800 x $10^{-9}$ s

From eq(1), we can conclude that the shortest distance to an object that this radar can detect:

$x_{min}$ = τc/2 => (800 x $10^{-9}$ x 3 x $10^{8}$ )/2

$x_{min}$ =120m

8 0

4 years ago

An object that is in free fall seems to be ______

bekas [8.4K]

An object that is in free fall seems to be (D) weightless.

Objects which are in free fall are said to be weightless because they only have the force of gravity acting upon them. Objects in free fall do not experience air resistance.

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3 years ago

When an object of mass m1 is hung on a vertical spring and set into vertical simple harmonic motion, its frequency is 12Hz. When

anzhelika [568]

Answer:

Explanation:

Given

When $m_1$ mass is attached to the spring its frequency is $f_1=12\ Hz$

when another mass $m_2$ is attached to $m_1$ , frequency changes to $f_2=4\ Hz$

frequency of spring mass system is given by

$f=\frac{1}{2\pi }\sqrt{\frac{k}{m}}$

for $m_1$

$f_1=\frac{1}{2\pi }\sqrt{\frac{k}{m_1}}$

$12=\frac{1}{2\pi }\sqrt{\frac{k}{m_1}}-----1$

for $m_1$ and $m_2$

$f_2=\frac{1}{2\pi }\sqrt{\frac{k}{m_1+m_2}}$

$4=\frac{1}{2\pi }\sqrt{\frac{k}{m_1+m_2}}----2$

divide 1 and 2

$3=\sqrt{\frac{m_1+m_2}{m_1}}$

squaring

$9=1+\frac{m_2}{m_1}$

$\frac{m_2}{m_1}=8$

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3 years ago

The line where the Earth and sky seem to meet forms the:

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The ocean and the sky provide a clean, flat line where the Earth seems to meet the sky. If you're standing on the beach looking out at the sea, the part of the sea that "touches" the horizon is called the offing

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3 years ago

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