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3 years ago

What made Mendeleev's periodic table particularly special?

1 answer:

4 0

Mendeleev's periodic table particularly special as he orchestrated the components by expanding nuclear mass and put components with comparative properties underneath one another.

Explanation: 

He gathers the components as per their properties adjusted some wrongly assigned nuclear masses. The course of action of components as indicated by their properties left some clear spaces in the table. He expected that the clear spaces spoke to components that had not yet been found.

He utilized his table to foresee the chemical and physical properties of five of the missing components. Three of these components were found in the following 15 years, and their properties firmly coordinated Mendeleev's forecasts. All chemists accepted at these points and acknowledged Mendeleev's Periodic Table.

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What would happen if the Earth stopped rotating?

trapecia [35]

Answer:

the atmosphere would still be in motion with the Earth's original 1100 mile per hour rotation speed at the equator. ... This means rocks, topsoil, trees, buildings, your pet dog, and so on, would be swept away into the atmosphere.

Explanation:

to me, this means we would proabaly be sucked into outer space and could die if no astronaut gear is on

4 0

3 years ago

At a maximum level of loudness, the power output of a 75-piece orchestra radiated as sound is 72.0 W. What is the intensity of t

FrozenT [24]

Answer:

The intensity would be 0.01432 W/ $m^{2}$

Explanation:

The sound intensity is the power that is transmitted by a sound wave per unit area.

Given that

Power output P of the 75-piece orchestra = 72.0 W

The listener's distance r = 20.0 m

The intensity of sound waves (I) can be obtained with the expression below;

I = P/A .............. 1

where P is the power

A is the area, in this case, at the distance r the sound is radiated through a sphere.

A = area of a sphere = 4π $r^{2}$

putting it into equation 1, the intensity would be;

I = P/ 4π $r^{2}$

Substituting our values we have;

I = 72.0 W / 4 π $20^{2}$ $m^{2}$

I = 0.01432 W/ $m^{2}$

Therefore the intensity would be 0.01432 W/ $m^{2}$

3 0

3 years ago

Can someone plz help me no links plz

Orlov [11]

Answer:

Im doing edge too rn-

Explanation:

Can you tell me the drop down options

7 0

3 years ago

Determine the moment of inertia Ixx of the mallet about the x-axis. The density of the wooden handle is 860 kg/m3 and that of th

Yuki888 [10]

Complete Question

Diagram for this shown on the first uploaded image

Answer:

The moment of inertia Ixx of the mallet about the x-axis is $I{xx}= 0.119 kg \cdot m^2$

Explanation:

From the question we are told that

The density `of wooden handle is $\rho_w = 860 kg/m^3$

The density `of soft-metal head is $\rho_s =8000kg/m^3$

Generally the mass of the wooden can be mathematically obtained with this formula

$m_w = \rho_w A_w l_w$

Where $A_w$ is mass of wooden handle which is mathematically obtain with the formula

$A_w = \frac{\pi}{4} d^2_w$

Where $d_w$ is the diameter of the wooden handle which from the diagram is

$27mm = \frac{27}{1000} = 0.027m$

So $A_w = \frac{\pi}{4} * 0.027^2$

$l_w$ is the length of the the wooden handle which is given in the diagram as $l_w = 315mm = \frac{315}{1000} = 0.315m$

Substituting these value into the formula for mass

$m_w = 860 * (\frac{\pi}{4} * 0.027^2 ) *0.315$

$= 0.155kg$

Generally the mass of the soft-metal head can be mathematically obtained with this formula

$m_s = \rho_s A_s l_s$

Where $A_s$ is mass of soft-metal head which is mathematically obtain with the formula

$A_s = \frac{\pi}{4} d^2_s$

Where $d_s$ is the diameter of the soft-metal head which from the diagram is

$36mm = \frac{36}{1000} = 0.036m$

So $A_s = \frac{\pi}{4} * 0.036^2$

$l_s$ is the length of the the soft-metal head which is given in the diagram

as $l_s = 90mm = \frac{90}{1000} = 0.090m$

Substituting these value into the formula for mass

$m_s = 8000 * (\frac{\pi}{4} * 0.036^2 ) *0.090$

$=0.733kg$

Generally the mass moment of inertia about x-axis for the wooden handle is

$(I_{xx})_w = [\frac{1}{3}m_w + l_w^2 ]$

Substituting values

$(I_{xx})_w = [\frac{1}{3}*0.155 + 0.315^2 ]$

$=5.12*10^{-3}kg \cdot m^2$

Generally the mass moment of inertia about x-axis for the soft-metal head is

$(I_{xx})_s = [\frac{1}{12}m_s l_s ^2 + b^2]$

Where b is the distance from the centroid to the axis of the head which is mathematically given as

$b=l_w +\frac{d_s}{2}$

Substituting values

$b = 0.315 + \frac{0.036}{2}$

$= 0.336m$

Now substituting values into the formula for mass moment of inertia about x-axis for soft-metal head

$(I_{xx})_s = [\frac{1}{12} *0.733* 0.090^2 + 0.336^2]$

$=0.113 kg \cdot m^2$

Generally the mass moment of inertia about x-axis is mathematically represented as

$I_{xx} = (I_{xx})_w + (I_{xx})_s$

$= [\frac{1}{3}m_w + l_w^2 ] + [\frac{1}{12}m_s l_s ^2 + b^2]$

Substituting values

$I_{xx} = 5.12*10^{-3} +0.113$

$I{xx}= 0.119 kg \cdot m^2$

8 0

3 years ago

El tren Lima la Orolla va a una velocidad de 10 km/h y de pronto aplica el freno por un derrumbe en la via. Si demora 18 segundo

Naya [18.7K]

Answer:

Distancia = 50.04 metros

Explanation:

Dados los siguientes datos;

Velocidad = 10 km/h

Tiempo = 18 segundos

Para encontrar la distancia;

Conversión:

10 km/h = 10 * 1000/3600 = 2.78 m/s

Distancia = velocidad * tiempo

Distancia = 2.78 * 18

Distancia = 50.04 metros

Por lo tanto, el tren viajaría 50.04 metros antes de detenerse por completo.

7 0

3 years ago