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jarptica [38.1K]
4 years ago
9

A wave with a greater amplitude will transfer . . . . \

Physics
1 answer:
BabaBlast [244]4 years ago
6 0

less mass is more mass but less energy in more mass. less mass has more energy

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A 12 g plastic ball is dropped from a height of 2.5 m and is moving at 3.2 m/s just before it hits the floor. How much mechanica
Nataly [62]

Answer:

0.24

Explanation:

Mass of ball= 12g=0.012Kg

height of ball= 2.5m

velocity of ball before falling= 3.2m/s

potential energy of the ball=mgh= 0.012*10*2.5=0.3J

kinetic energy of the ball=0.5*mv^{2}=0.5*0.012*3.2*3.2=0.6J

Loss in mechanical energy during the fall= potential energy- Kinetic energy= 0.3-0.06=0.24J

note: During the fall, the potential energy of the ball is converted to kinetic energy. the loss in energy is due to air resistance.

4 0
3 years ago
Is the universe endless, how and why?
Grace [21]

Answer:

Unknown

Explanation:

Because we cannot observe space beyond the edge of the observable universe, it is unknown whether the size of the Universe in its totality is finite or infinite.

6 0
3 years ago
Read 2 more answers
The greatest height reported for a jump into an airbag is 99.4 m by stuntman Dan Koko. In 1948 he jumped from rest from the top
vaieri [72.5K]

Answer:

v = 44,16 m/s

Explanation:

We will fixate our reference in the starting point from where Dan jumped of, at the top of the Casino. Therefore, the displacement made when dan reached the airbag would be of y= -99,4 m viewed from our reference. We describe the motion of dan with the equation:

v_y^2 =v_0^2 +2ay

Dan jumped from the rest, that means that the initial velocity v_0=0, therefore:

 v_y^2 =2ay \rightarrow v_y = \sqrt{2ay}

Since Dan is moving in the negative axis regarding our reference point, we take the negative root of the equation.

v_y=-√(2*(-9,81 m/s^2 )*(-99,4 m) )=44,1613 m/s  v_y =- \sqrt{2*(-9,81 m/s^2)*(-99,4 m)} = 44,1613 m

So, if we don’t take the air resistance into account, Dan would have achieved an velocity of 44,16 m/s when he reached the airbag.

I hope everything was clear with my explanation. If you need anything else, let me know. Have a great day :D

7 0
4 years ago
If the absolute pressure of a gas is 550.280 kPa, its gage pressure is
aivan3 [116]

By definition we have to:

Pabs = Patm + Pg

Where,

Pabs: absolute pressure

Patm: atmospheric pressure

Pg: gage pressure

The atmospheric pressure is constant and its value is:

Patm = 101.325 kPa

Then, by clearing gage pressure we have:

Pg = Pabs - Patm

Substituting values we have:

Pg = 550.280 - 101.325\\Pg = 448.955 KPa

Answer:

If the absolute pressure of a gas is 550.280 kPa, its gage pressure is:

D. 448.955 kPa

4 0
3 years ago
Read 2 more answers
When a wave hits an object,energy from the wave is both absorbed and reflected off the object
poizon [28]
I believe the statement is true. Have a good day.
5 0
3 years ago
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