Answer:
a. U = 1.68 μJ
b. i = 7.39 mA
Explanation:
a.
The energy total of the circuit can be find using
U = Q ² / 2 * C
Q = 3.56 μC
C = 3.77 μF
U = (3.56 μC ) ² / 2 * 3.77 μF
U = 1.6808 x 10 ⁻⁶ J
U = 1.68 μJ
b.
Now to determine the current in the circuit
U = ¹/₂ * L * i²
i² = 2 * U / L
i = √ 2 * U / L
i = √2 * 1.68 μJ / 61.5 mH
i = 7.39 mA
Answer:
a) Ffloor = 616.56[N]
b) Ffloor = 484.16 [N]
Explanation:
In order to solve this problem, we must first make a free body diagram. In this free body diagram include forces, as well as acceleration.
Then after the free body diagram, we perform a force analysis by means of Newton's second law, where the upward forces and even the upward acceleration will be taken as positive.
ΣF = m*a
where:
F = force [N] (units of Newtons]
m = mass [kg]
a = acceleration [m/s²]
g = gravity acceleration = 9,81 [m/s²]
a)
b) Using Newton's second law we have.
Answer:
Torque on the coil will be ZERO
Explanation:
As we know that the magnetic moment of the closed current carrying coil is always along its axis and it is given as
now we know that magnetic field is also along the axis of the coil so here as we know the equation of torque given as
so we have
Answer :the resultant of two vectors can be found using either the parallelogram method or the triangle method. don't know if this was helpful ?
Explanation: