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3 years ago

Last year, Ken bought a $300 mountain bike. His bike has depreciated by 20% since he bought it. What is

Mathematics

1 answer:

trapecia [35]3 years ago

3 0

Answer:

Step-by-step explanation:

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Consider the sequence 16,-8,4,-2,1,

Lana71 [14]

This is a geometric progression pattern with the common ratio of negative 0.5.

The next three would be -0.5, followed by 0.25, followed by -0.125

5 0

3 years ago

BBC News had 6,632,512 viewers for its evening bulletin. What is the place value of the 3?

VashaNatasha [74]

6,632,512

the place value of the 3 is 30,000

hope it helps

6 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B80%7D%20" id="TexFormula1" title=" \sqrt[3]{80} " alt=" \sqrt[3]{80} " ali

Marianna [84]

Start by decomposing the number inside the root into primes

Then group the terms into cubes if possible

$\begin{gathered} 80=2\cdot2\cdot2\cdot2\cdot5 \\ 80=2^3\cdot2\cdot5 \\ 80=10\cdot2^3 \end{gathered}$

rewrite the root

$\sqrt[3]{80}=\sqrt[3]{10\cdot2^3}$

then cancel the terms that are cubes and bring them out of the root

$\sqrt[3]{80}=2\sqrt[3]{10}$

7 0

1 year ago

Rounding number to the nearest hundredth

bearhunter [10]

Answer:

the answer is 11.66

Step-by-step explanation:

because 3 cant give 0 anything 9 will make 1, 2 but 2 cant change 6

6 0

2 years ago

Read 2 more answers

The volume

Sedaia [141]

$\bf \begin{array}{cccccclllll}
\textit{something}&&\textit{varies directly to}&&\textit{something else}\\ \quad \\
\textit{something}&=&{{ \textit{some value}}}&\cdot &\textit{something else}\\ \quad \\
y&=&{{ k}}&\cdot&x
&& y={{ k }}x
\end{array}\\ \quad \\
$

and also

$\bf \begin{array}{llllll}
\textit{something}&&\textit{varies inversely to}&\textit{something else}\\ \quad \\
\textit{something}&=&\cfrac{{{\textit{some value}}}}{}&\cfrac{}{\textit{something else}}\\ \quad \\
y&=&\cfrac{{{\textit{k}}}}{}&\cfrac{}{x}
&&y=\cfrac{{{ k}}}{x}
\end{array}
$

now, we know that V varies directly to T and inversely to P simultaneously
thus $\bf V=T\cdot \cfrac{k}{P}$

so $\bf V=T\cdot \cfrac{k}{P}\qquad 
\begin{cases}
V=42\\
T=84\\
P=8
\end{cases}\implies 42=\cfrac{84k}{8}\implies 4=k
\\\\\\
V=\cfrac{4T}{P}\qquad now\quad 
\begin{cases}
V=74\\
P=10
\end{cases}\implies 74=\cfrac{4T}{10}\implies 185=T$

7 0

3 years ago