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sergey [27]
3 years ago
6

Of all the people applying for a certain​ job, 60% are qualified and 40​% are not. The personnel manager claims that she approve

s qualified people 70​% of the​ time; she approves unqualified people 30​% of the time. Find the probability that a person is qualifiedqualified if he or she was approvedapproved by the manager.

Mathematics
1 answer:
Sladkaya [172]3 years ago
6 0

Answer:0.778

Step-by-step explanation:

Given

60 % are qualified for Job and 40  % are not

Out of qualified manager approves 70 %

out of not qualified manager approves 30 %

Total no of approved people=0.6\times 0.7+0.4\times 0.3=0.54

Probability of qualified and Approved by manager=0.6\times 0.7=0.42

P(person is qualified if he or she was approved by the manager)=\frac{0.42}{0.54}=0.778

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Find the slope of the line that contains the points (–2, 7) and (–7, –6). Match your results to the correct answer below.
atroni [7]

Answer:

13/5

Step-by-step explanation:

slope is the change in y over the change in x

-6 - 7 divided by -7 - (-2)

-13/-5 or 13/5

8 0
3 years ago
Ernesto plans to build a pen for his pet iguana. Think about these two different questions. What is the area of the largest rect
Allisa [31]
The area of the rectangular pen is 10,000 m² and the area of the circular pen is 12,738.95 m².

For the rectangular pen, we want the sides to be congruent.  To minimize perimeter and maximize area, the figure needs to be equilateral.

400/4 = 100 m for each side

This means that the area is 100(100) = 10,000 m².

If the pen is circular, this means the circumference is 400 m.  Circumference is given by the formula C=πd:

400 = 3.14d

Divide both sides by 3.14:
400/3.14 = 3.14d/3.14
127.389 = d

The radius is half of the diameter:
r = 127.389/2 = 63.6945

The area of the circle is given by A=πr²:

A=3.14(63.6945)² = 12738.9465 ≈ 12738.95 m²
6 0
3 years ago
A. figure P<br> B. figure R<br> C. figure S<br> D. figure G
vodomira [7]

Answer:

D. figure G

Step-by-step explanation:

4 0
2 years ago
Two possible solutions of √11-2x=√x^2+4x+4 are –7 and 1. Which statement is true? A) Only x = –7 is an extraneous solution.
11111nata11111 [884]

Answer:

Option D)Neither solution is extraneous.

Step-by-step explanation:

we have

\sqrt{11-2x}=\sqrt{x^{2}+4x+4}

we know that

two possible solutions are x=-7 and x=1

<u><em>Verify each solution</em></u>

Substitute each value of x in the expression above and interpret the results

1) For x=-7

\sqrt{11-2(-7)}=\sqrt{-7^{2}+4(-7)+4}

\sqrt{25}=\sqrt{25}

5=5 ----> is true

therefore

x=-7 is not a an extraneous solution

2) For x=1

\sqrt{11-2(1)}=\sqrt{1^{2}+4(1)+4}

\sqrt{9}=\sqrt{9}

3=3 ----> is true

therefore

x=1 is not a an extraneous solution

therefore

Neither solution is extraneous

7 0
3 years ago
Read 2 more answers
If U = {x: X € N, 1 &lt; × &lt; 15)
Inessa05 [86]

Answer:

Step-by-step explanation:

Given:

U = {x: X € N, 1 < × < 15) = {1,2,3,4,5,6,7,8,9,10,11,12,13,14,15}

A = {2,4,6,8,10,12,14}

B = {3,6,9,12,15}

C = {5,10,15}

(a) Verify A(BnB)=(AUB)(AUB)

A U (B n B)

=  {2,4,6,8,10,12,14} U (  {3,6,9,12,15} n  {3,6,9,12,15} )

=  {2,4,6,8,10,12,14} U {3,6,9,12,15}

=  {2,3,4,6,8,9,10,12,14,15}

( A U B) n (A U B)

= {2,3,4,6,8,9,10,12,14,15} n {2,3,4,6,8,9,10,12,14,15}

= {2,3,4,6,8,9,10,12,14,15}

Therefore

A U (B n B)  =  ( A U B) n (A U B)

verifies

(b) Verify An(BUC)=(AnB)u(AnC)

A n ( B U C)

=  {2,4,6,8,10,12,14} n ( {3,6,9,12,15} U {5,10,15} )

=  {2,4,6,8,10,12,14} n {3,5,6,9,10,12,15}

= {6,10,12}

( A n B ) U ( A n C )

= ( {2,4,6,8,10,12,14} n {3,6,9,12,15} ) U ( {2,4,6,8,10,12,14} n {5,10,15} )

= {6,12} U {10}

= {6,10,12}

Therefore

A n ( B U C) = ( A n B ) U ( A n C )

verifies

(c) Verify AU(BUC)=(AUB)U(AUC)​

AU(BUC)

=  {2,4,6,8,10,12,14}U{3,6,9,12,15}U{5,10,15}

= {2,3,4,5,6,8,9,10,12,14,15}

(AUB)U(AUC)​

=  ({2,4,6,8,10,12,14}{3,6,9,12,15})U({2,4,6,8,10,12,14}U{5,10,15})

= {2,3,4,6,8,9,10,12,14,15}U{2,4,5,6,8,10,12,14,15}

= {2,3,4,5,6,8,9,10,12,14,15}

Therefore

AU(BUC)=(AUB)U(AUC)​

verifies

5 0
3 years ago
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