The probability for choosing green and red is 
<u>Solution:</u>
Given that , A bag contains 1 red, 1 yellow, 1 blue, and 1 green marble.
We have to find what is the probability of choosing a green marble, not replacing it, and then choosing a red marble?
Now, we know that,

So, total possible outcomes = 1 red + 1 yellow + 1 blue + 1 green = 4

And now, total outcomes will be only 3 as we are not replacing the picked marble.

Hence, the probability for choosing green and red is 
Answer:
48 is right!!
Step-by-step explanation:
the pattern is +10 +9 +8 +7 +6 +5 and so on
Answer:
The required probability is, 
Step-by-step explanation:
Of 24 employees at a local supermarket, 13 work as cashiers and 11 stock shelves. If 4 employees are selected at random to work overtime, then
P( all 4 are cashiers) = 

4(2 - x) > -2x - 3(4x + 1)
8 - 4x > -2x - 12x - 3
-4x + 2x + 12x > -3 - 8
10x > -11
x > -11/10
x > -1.1
Therefore, x = 0 and x = 10 zre solutions to the inequality.
Answer:
All rational numbers less than 7
Step-by-step explanation: