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lorasvet [3.4K]
3 years ago
6

All forms of energy can do work. True or False

Physics
1 answer:
erik [133]3 years ago
3 0
True since the defencion of energy is "something that lets something do work" the only thing that changes is the energy after the work which can then be used to do different work
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For a short period of time, the frictional driving force acting on the wheels of the 2.5-Mg van is N, where t is in seconds. If
KATRIN_1 [288]

Answer:

15.6m/s

Completed Question;

For a short period of time, the frictional driving force acting on the wheels of the 2.5-Mg van is N= 600t^2 , where t is in seconds. If the van has a speed of 20 km/h when t = 0, determine its speed when t = 5

Explanation:

Mass m = 2500kg

Speed v1 = 20km/h = 20/3.6 m/s = 5.556 m/s

To determine speed v2;

Using the principle of momentum and impulse;

mv1 + ∫₀⁵ F dt = mv2

8 0
3 years ago
A transformer has 1000 turns in the primary coil and 100 turns in the secondary coil. If the primary coil is connected to a 120
Marianna [84]

Answer:

The voltage on the secondary is 12 V while the current is 0.5 A.

Explanation:

A transformer works by changing the level of the voltage and current on a circuit using a magnetic field and two coils. The ratio by wich they are changed is dependant on the ratio of turns between the primary and secondary of the transformer. In this case we have a ratio for the voltage of:

ratio = (turns on the secondary)/(turns on the primary)

ratio = 100/1000 = 0.1

So in this case the voltage delivered to the primary will be multiplied by 0.1. We can now calculate the voltage on the secondary:

Voltage secondary = Voltage primary* ratio = 120*0.1 = 12 V

The transformer maintains roughly the same power output on both sides, since the power output on a electric circuit is given by the product of the voltage by the current on that circuit, to maintain the same power when the voltage has been droped the current must be raised by the same ratio. So we have:

Current secondary = Current primary*(1/ratio) =0.05*(1/0.1) = 0.5 A

6 0
3 years ago
Although it may seem like it, a wave’s frequency and its speed are not the same. Picture yourself standing on the side of a road
Verizon [17]

Answer:

A) the space inbetween the waves

B) frequency

C) the frequency gets higher

Explanation:

5 0
3 years ago
A force of constant magnitude pushes a box up a vertical surface, as shown in the figure.
Ray Of Light [21]

The work done on the box by the applied force is zero.

The work done by the force of gravity is 75.95 J

The work done on the box by the normal force is 75.95 J.

<h3>The given parameters:</h3>
  • Mass of the box, m = 3.1 kg
  • Distance moved by the box, d = 2.5 m
  • Coefficient of friction, = 0.35
  • Inclination of the force, θ = 30⁰

<h3>What is work - done?</h3>
  • Work is said to be done when the applied force moves an object to a certain distance

The work done on the box by the applied force is calculated as;

W = Fd cos(\theta)\\\\W = (ma)d \times cos(\theta)

where;

a is the acceleration of the box

The acceleration of the box is zero since the box moved at a constant speed.

W = (0) d \times cos(30)\\\\W = 0 \ J

The work done by the force of gravity is calculated as follows;

W = mg \times d\\\\W = 3.1 \times 9.8 \times 2.5 \\\\W = 75.95 \ J

The work done on the box by the normal force is calculated as follows;

W = (F_n) \times d\\\\W = (mg + F sin\theta) \times d\\\\W = (mg + 0) \times d\\\\W = mgd\\\\W = 3.1 \times 9.8 \times 2.5\\\\W = 75.95 \ J

Learn more about work done here: brainly.com/question/8119756

8 0
2 years ago
A bullet with a mass of 0.3 kg is fired out of a gun with a mass of 4 kg at 600 m/s. What is the recoil velocity on the gun?
slavikrds [6]

Answer:

According to the Conservation of Momentum,

Momentum of the gun = momentum of the bullet

M(gun)×V(gun)=m(bullet)×v(bullet)

4kg × V = 0.3kg × 600m/s²

V = (0.3 × 600)/4 = 45 m/s

The recoil velocity on the gun is <em><u>45 m/s</u></em>

<h3><u>45 m/s</u> is the right answer.</h3>
4 0
3 years ago
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