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rewona [7]
3 years ago
13

For a short period of time, the frictional driving force acting on the wheels of the 2.5-Mg van is N, where t is in seconds. If

the van has a speed of 20 km/h when t = 0, determine its speed when t = 5 s.
Physics
1 answer:
KATRIN_1 [288]3 years ago
8 0

Answer:

15.6m/s

Completed Question;

For a short period of time, the frictional driving force acting on the wheels of the 2.5-Mg van is N= 600t^2 , where t is in seconds. If the van has a speed of 20 km/h when t = 0, determine its speed when t = 5

Explanation:

Mass m = 2500kg

Speed v1 = 20km/h = 20/3.6 m/s = 5.556 m/s

To determine speed v2;

Using the principle of momentum and impulse;

mv1 + ∫₀⁵ F dt = mv2

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Officials begin the remove water from a full man made lake

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6 0
3 years ago
You are standing next to a table and looking down on a record player sitting on the table. Take the spindle (axis of rotation) t
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Answer:

a) the rotational speed of the clay is  3.45 rad/s

b) the value of A in the equation of motion is 0.15 m

c) the value of ϕi is 90° or π/2 rad.

Explanation:

 Given that;

Revolution per minute rpm = 33( 1/3) =  100/3

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a)

Rotational speed W = 2πf

we substitute

W = 2π × 0.55

W = 3.45 rad/s

Therefore, the rotational speed of the clay is  3.45 rad/s

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since y(t) has the maximum value at t =0

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= 0.15sin(90°)

= 0.15

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2 years ago
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3 0
3 years ago
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