The change in velocity (v₂ - v₁) is
<em> (-20) / (the object's mass)</em>.
Call it a crazy hunch, but I can't shake the feeling that there was more
to the question before the part you copied, that mentioned the object's
mass, and its velocity before this force came along.
Answer:
B. people with OCD know their disorder is irrational
Explanation:
Got it right
Imagine you are in a swimming pool 30m deep. Assuming you know that water is denser than air, you would know that the 30m of water above you will carry more weight, and press down on your body. Say you were in a swimming pool 60m deep, you would be sandwiched between 30m of water pressing down on you, and the upthrust created by the 30m of water below you.
In a building 30m up, the pressure will be regulated, as you are in a building. The floor will be strong enough to support the weight of the body, and the body will not recoil into itself.
Answer:
2.2 meters
Explanation:
Potential energy, PE created by a charge, q at a radius r from the charge source, Q, is expressed as:
![KE=\frac{kQq}{r}\ \ \ \ \ \ \ ...i](https://tex.z-dn.net/?f=KE%3D%5Cfrac%7BkQq%7D%7Br%7D%5C%20%20%20%20%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20...i)
is Coulomb's constant.
#The electric field,
at radius r is expressed as:
![E=\frac{kQ}{r^2}\ \ \ \ \ \ \ \ \ \ ...ii](https://tex.z-dn.net/?f=E%3D%5Cfrac%7BkQ%7D%7Br%5E2%7D%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20...ii)
From i and ii, we have:
![KE=Eqr](https://tex.z-dn.net/?f=KE%3DEqr)
![r=(KE)/Eq](https://tex.z-dn.net/?f=r%3D%28KE%29%2FEq)
#Substitute actual values in our equation:
![r=\frac{75J}{(7.2\times 10^{-5}C)(4.8\times 10^5 V/m)}\\\\=2.1701\approx2.2\ m](https://tex.z-dn.net/?f=r%3D%5Cfrac%7B75J%7D%7B%287.2%5Ctimes%2010%5E%7B-5%7DC%29%284.8%5Ctimes%2010%5E5%20V%2Fm%29%7D%5C%5C%5C%5C%3D2.1701%5Capprox2.2%5C%20m)
Hence, the distance between the charge and the source of the electric field is 2.2 meters