All categories

2 years ago

A block of wood has the mass of 180 grams. It is 10cm long, 6cm wide and

Mathematics

1 answer:

pychu [463]2 years ago

5 0

Answer:

$.75g/cm^3$

Step-by-step explanation:

density = mass / volume

We already know the mass - 180g

Find the volume

$10cm * 6cm * 4cm = 240 cm^{3}$

Plug in the volume and mass in the density formula

$density = 180g / 240cm^{3}$

Simplify

$Density = .75g/cm^{3}$

You might be interested in

Abby counts 12 large boxes and 18 small boxes of pencils in the supply cabinet. Each large box contains 144 pencils . Each small

BigorU [14]

Answer:

2,160 pencils

Step-by-step explanation:

Large boxes = 12

Small boxes = 18

Each large box contains 144 pencils . Each small box contains 24 pencils

Total pencil in large boxes = Total large boxes × number of pencils per box

= 12 × 144

= 1,728 pencils

Total pencil in small boxes = Total small boxes × number of pencils per box

= 18 × 24

= 432 pencils

Estimate the total number of of pencils

Total number of pencils = total pencils in large boxes + total pencil in small boxes

= 1,728 pencils + 432 pencils

= 2,160 pencils

It is better to have an underestimate than an overestimate so that you won't disappoint your buyers when they request for a quantity of supply. If it is underestimated; you can meet demand, if it is overestimated; you can't meet demand

3 0

3 years ago

A model rocket is launched with an intitial upupward velocity of 202 ft/s. The rocket’s height h (in feet) after seconds is give

dsp73

Given that the height of a object thrown within a gravitational field is given as a quadratic equation in time, t, the time at which the object is at a specified height can be found by the quadratic formula

The values of, t, for which the height of the rocket is 82 feet are;

t = 12.21 seconds or t = 0.42 seconds

Question: Parts of the question that appear missing but can be found online are (i) To find the values of the time, t, when the rocket's height is 82 feet and round answers to the nearest hundredth

The known parameters of the rocket are;

The initial upward velocity of the rocket, v = 202 ft./s

The given function representing the height, h, (in feet) after t seconds is presented as follows;

H = 202·t - 16·t²

The unknown;

The time for which the height of the rocket is 82 feet

Method;

Substitute H = 82 feet in the height function equation and solve for t as follows;

When H = 82, we get;

82 = 202·t - 16·t²

Therefore;

16·t² - 202·t + 82 = 0

Dividing the above equation by 2 gives;

(16·t² - 202·t + 82)/2 = 0/2

8·t² - 101·t + 41 = 0

By using the quadratic formula, we get;

$\mathbf{t = \dfrac{101 \pm \sqrt{(-101)^2 - 4 \times 8 \times 41} }{2 \times 8} = \dfrac{101 \pm \sqrt{8889} }{16}}$

Therefore, the values of t given by rounding off to the nearest hundredth are;

t = 12.21 or t = 0.42

The values of the time, t, at which the height of the rocket is 82 feet are t = 12.21 seconds or t = 0.42 seconds

Learn more about equation models of height as a function of time here;

brainly.com/question/84352

7 0

3 years ago

Why was proffessor clabberhead utterbunk holding up a piece of bread

Gnesinka [82]

He's a silly goober and he likes to joke around

6 0

3 years ago

Suppose that your business is operating at the 4.5-Sigma quality level. If projects have an average improvement rate of 50% annu

Luda [366]

Answer:

11.75 years

Step-by-step explanation:

If we ignore the fact that "6-sigma" quality means the error rate corresponds to about -4.5σ (3.4 ppm) and simply go with ...

P(z ≤ -6) ≈ 9.86588×10^-10

and

P(z ≤ -4.5) ≈ 3.39767×10^-6

the ratio of these error rates is about 0.000290372. We're multiplying the error rate by 0.5 each year, so we want to find the power of 0.50 that gives this value:

0.50^t = 0.000290372

t·log(0.50) = log(0.00290372) . . . . take logarithms

t = log(0.000290372)/log(0.50) ≈ -3.537045/-0.301030

t ≈ 11.75

It will take about 11.75 years to achieve Six Sigma quality (0.99 ppb error rate).

_____

Comment on Six Sigma

A 3.4 ppm error rate is customarily associated with "Six Sigma" quality. It assumes that the process may have an offset from the mean of up to 1.5 sigma, so the "six sigma" error rate is P(z ≤ (1.5 -6)) = P(z ≤ -4.5) ≈ 3.4·10^-6.

Using that same criteria for the "4.5-Sigma" quality level, we find that error rate to be P(z ≤ (1.5 -4.5)) = P(z ≤ -3) ≈ 1.35·10^-3.

Then the improvement ratio needs to be only 0.00251699, and it will take only about ...

t ≈ log(0.00251699)/log(0.5) ≈ 8.6 . . . . years

5 0

3 years ago

"India is the second most populous country in the world, with a population of over 1 billion people. Although the government has

Leto [7]

Answer:

0.54,0.46,0.43

Step-by-step explanation:

Given that India is the second most populous country in the world, with a population of over 1 billion people.

The pdf of household size say X in India varies from 1 to 8.

The distribution is shown as follows

X 1 2 3 4 5 6 7 8 Total

P 0.02 0.09 0.18 0.25 0.20 0.12 0.08 0.06 1.00

a) the probability that there are less than 5 members in a household in India

= $P(X$

= $P(1 to 4) = 0.54$

b. the probability that there are 5 or more members in a typical household

in India

= $P(X\geq 5) = P(5 to 8)\\\\= =0.46$

c) the probability that the number of members in a typical household in India is strictly between 2 and 5

$=P(2$

4 0

3 years ago