12, 2, 4, and 7. The coefficients in the expression 12xy³+2x⁵y+4x⁵y²+7x⁵y are 12, 2, 4, and 7.
In order to solve this problem we have to know that the coefficients is a factor linked to a monomial. For example, the first monomial of the equation is 12xy³ the coeffcient of xy³ is 12.
Answer:
Using ∣x∣>a⇒x<−a or x>a, we get
∣3x−7∣>4⇒3x−7<−4 or 3x−7>4
⇒3x<3 or 3x>11⇒x<1 or x>
3
11
⇒x∈(−∞,1)∪(
3
11
,∞).
Answer:
x= -1
Step-by-step explanation:
Solving through linear equation,
-0.1x + 3/10= 4/10
Bring 3/10 to the other side making it minus
-0.1x = 4/10 - 3/10
-0.1x = (4-3)/10
-0.1x= 1/10
Bring -0.1 to the other side n divide
x= 1/10 ÷ -0.1
( Note that -0.1 is the same as -1/10)
x = 1/10 ÷ -1/10
= 1/10*-10/1
= -10/10
= -1
The answer is C.) line segment
