<span>the balanced eqaution for the combustion of C2H2 is as follows 2</span>C₂H₂ + 5O₂ --> 4CO₂ + 2H₂<span>O
stoichiometry of C</span>₂H₂ to H₂<span>O is 2:2 . Number of moles of </span>C₂H₂ = mass present / molar mass of C₂H₂ <span> Since molar mass of </span>C₂H₂ <span> is 26 g/mol. Number of </span>C₂H₂ <span> moles reacted = 64.0 g / 26 g/mol = 2.46 mol. according to molar ratio of 2:2. the number of H</span>₂O moles formed = number of C₂H₂ <span> moles reacted. Therefore number of H</span>₂<span>O moles produced = 2.46 mol </span>