Out of the given options, weight is influenced by mass and gravity
Answer: Option A
<u>Explanation:
</u>
The object's mass is defined as the quantity of a matter with which the object is formed. It can change its state of matter but the quantity will remain the same. However, the weight is defined as how much force gravity exerts on the object's mass to pull it.
The mass is always same irrespective the location but the weight may vary from one place to the other while talking for the bigger picture. For example, the object's weight may be 60 kg on Earth but when it is measured on the moon, it will be lesser.
The weight of an object generally has nothing doing with the volume and it doesn't depend solely on the gravitational pull. The mass plays a crucial role.
Answer:
B
Explanation:
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Answer:
Explanation:
Force between two charges can be expressed as follows
F = k q₁ q₂ / d²
q₁ and q₂ are two charges , d is distance between them , k is a constant whose value is 9 x 10⁹
distance between charges is fixed which is 4 -2 = 2 cm = 2 x 10⁻² m
force between 1μC and 4μC
= 9 x 10⁹ x 1 x 4 x 10⁻¹² / ( 2 x 10⁻² )²
= 9 x 10 = 90 N
force between 4μC and 1μC
= 9 x 10⁹ x 4 x 1 x 10⁻¹² / ( 2 x 10⁻² )²
= 9 x 10 = 90 N
force between 2μC and 2μC
= 9 x 10⁹ x 2 x 2 x 10⁻¹² / ( 2 x 10⁻² )²
= 9 x 10 = 90 N
force between 1μC and 2μC
= 9 x 10⁹ x 1 x 2 x 10⁻¹² / ( 2 x 10⁻² )²
= 4.5 x 10 = 45 N
force between 1μC and 8μC
= 9 x 10⁹ x 1 x 8 x 10⁻¹² / ( 2 x 10⁻² )²
= 18 x 10 = 180 N
force between 2μC and 8μC
= 9 x 10⁹ x 1 x 8 x 10⁻¹² / ( 2 x 10⁻² )²
= 36 x 10 = 360 N
Left Charge Right Charge Resulting force(N)
1μC 4μC 90 N
4μC 1μC 90 N
2μC 2μC 90 N
1μC 2μC 45 N
1μC 8μC 180 N
2μC 8μC 360 N
Explanation:
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Answer:
The charge stored in the capacitor will stay the same. However, the electric potential across the two plates will increase. (Assuming that the permittivity of the space between the two plates stays the same.)
Explanation:
The two plates of this capacitor are no longer connected to each other. As a result, there's no way for the charge on one plate to move to the other. 
, the amount of charge stored in this capacitor, will stay the same.
The formula 
relates the electric potential across a capacitor to:
- , the charge stored in the capacitor, and
, the capacitance of this capacitor.
While stays the same, moving the two plates apart could affect the potential 
by changing the capacitance of this capacitor. The formula for the capacitance of a parallel-plate capacitor is:
,
where
is the permittivity of the material between the two plates.
is the area of each of the two plates.
is the distance between the two plates.
Assume that the two plates are separated with vacuum. Moving the two plates apart will not affect the value of . Neither will that change the area of the two plates.
However, as (the distance between the two plates) increases, the value of will become smaller. In other words, moving the two plates of a parallel-plate capacitor apart would reduce its capacitance.
On the other hand, the formula can be rewritten as:
.
The value of (charge stored in this capacitor) stays the same. As the value of becomes smaller, the value of the fraction will become larger. Hence, the electric potential across this capacitor will become larger as the two plates are moved away from one another.
