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Mademuasel [1]
3 years ago
15

A woman lifts a 300 newton child a distance of 1.5 meters in 0.75 seconds. What is her power output in lifting the child?

Physics
1 answer:
Nitella [24]3 years ago
7 0
Power = Work done / time

Work done = Force * Distance
                 =  300 N *  1.5 m =  450 J

Power =  450 / 0.75 = 600 Watts.
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A 6 kg box with initial speed 5 m/s slides across the floor and comes to a stop after 1.9 s. What is the coefficient of kinetic
Ilia_Sergeevich [38]

Answer:

\mu_k=0.27

Explanation:

According to the free body diagram, in this case, we have:

\sum F_x:-F_k=ma\\\sum F_y:N=mg

Recall that the force of friction is given by:

F_k=\mu_k N

Replacing and solving for the coefficient of kinetic friction:

-\mu_kN=ma\\-\mu_k(mg)=ma\\\mu_k=-\frac{a}{g}

We have an uniformly accelerated motion. Thus, the acceleration is defined as:

a=\frac{v_f-v_0}{t}\\a=\frac{0-5\frac{m}{s}}{1.9s}\\a=-2.63\frac{m}{s^2}

Finally, we calculate \mu_k:

\mu_k=-\frac{-2.63\frac{m}{s^2}}{9.8\frac{m}{s^2}}\\\mu_k=0.27

4 0
3 years ago
Si la fuerza de repulsión entre dos cargas es 18 × 1013
sattari [20]

Answer:

Explanation:

F = kQq/r²

r = √(kQq/F)

a)  r = √(8.899(10⁹)(8)(4) / 18(10¹³)) = 0.0397749... m

  r = 40 mm

b) r = √(8.899(10⁹)(12)(3) / 18(10¹³)) = 0.0421876... m

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5 0
3 years ago
You are looking down on a N = 9 turn coil in a magnetic field B = 0.5 T which points directly down into the screen. If the diame
Novay_Z [31]

Answer:

The magnitude of the voltage is 2.27\times10^{-4}\ V and the direction of the current is clockwise.

Explanation:

Given that,

Number of turns = 9

Magnetic field = 0.5 T

Diameter = 3 cm

Time t = 0.14 s

We need to calculate the flux

Using formula of flux

\phi=NAB

Put the value into the formula

\phi=9\times\pi\times(1.5\times10^{-2})^2\times0.5

\phi=0.003180

We need to calculate the emf

Using formula of emf

\epsilon=-\dfrac{d\phi}{dt}

\epsilon=-\dfrac{0.003180}{0.14}

\epsilon =-0.000227\ V

\epsilon=-2.27\times10^{-4}\ V

Negative sign shows the direction of current.

Hence, The magnitude of the voltage is 2.27\times10^{-4}\ V and the direction of the current is clockwise.

8 0
4 years ago
A dragster takes off from rest and crosses the finish line 320 m away. If the dragster is able to accelerate at 10LaTeX: \frac{m
Rasek [7]

Answer:

t = 8 s

Explanation:

In order to find the time taken by the dragster we will use equations of motion. Here, we will use second equation of motion:

s = Vi t + (1/2)at²

where,

s = distance covered = 320 m

Vi = Initial Velocity = 0 m/s (Since, dragster starts from rest)

t = time taken = ?

a = acceleration of dragster = 10 m/s²

Therefore,

320 m = (0 m/s)t + (1/2)(10 m/s²)t²

t² = (320 m)(2)/(10 m/s²)

t = √(64 s²)

<u>t = 8 s</u>

3 0
3 years ago
Read 2 more answers
So lost on this one number 1 ?
kirza4 [7]

Read each statement, one at a time, and form the picture in your mind.

<em>Statement #1</em> should make you feel all warm and fuzzy inside.

Statements #2, #3, and #4 should make your red flag wave on the inside, and should make you giggle on the outside when you realize how absurd each of those is.

5 0
3 years ago
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