A woman lifts a 300 newton child a distance of 1.5 meters in 0.75 seconds. What is her power output in lifting the child?

Physics

1 answer:

Nitella [24]3 years ago

7 0

Power = Work done / time

Work done = Force * Distance
= 300 N * 1.5 m = 450 J

Power = 450 / 0.75 = 600 Watts.

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Plsss help

Ede4ka [16]

Work = force x distance. In units, Joules = Newtons x meters.

So: Work = 50 Newtons x 3 meters

Work = 150 joules. Answer D is correct

FYI - to ace physics, you should learn to identify these values using their fundamental units:
Force = Newtons = Kg·m/s²
Work = joules = kg·m²/s²
Power = watts = kg·m²/s³

In high school physics, If you learn to arrange equations so the units work out properly for the answer, you'll get most problems correct.

7 0

3 years ago

In a double slit experiment, the distance between the slits is 0.2 mm and the distance to the screen is 100 cm. What is the phas

Anni [7]

Answer:

The phase difference is $\Delta \phi = 180^o$

Explanation:

From the question we are told that

The distance between the slits is $d = 0.2 \ mm = \frac{0.2}{1000} = 0.2 *10^{-3} \ m$

The distance to the screen is $D = 100 cm = \frac{100}{100} = 1 \ m$

The wavelength is $\lambda = 400nm$

The distance of the wave from the central maximum is $L = 5mm = 5*10^{-3} m$

Generally the path difference of this waves is mathematically represented as

$y = d sin \theta$

Here $\theta$ is the angle between the the line connecting the mid-point of the slits with the screen and the line connecting the mid-point of the slits to the central maximum