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Zepler [3.9K]
2 years ago
5

0.66666667 as a fraction

Mathematics
2 answers:
Ierofanga [76]2 years ago
7 0

Answer:

__________________________________________

    The correct answer is:   " \frac{2}{3} " .

__________________________________________

Note:  Let's assume that this given decimal value  is really:

"0.66666666666666666....."  ;

(non-terminating; but repeating the singing digit, "7" ; yet rounded to:

" 0.66666667 " ;  

then:  " 0.666... "    = \frac{666}{999}  ;

                             

                               =  (666 ÷ 111) / (999 ÷ 111)  ;

                               =  6/9 ;

                              = (6÷3)/(9÷3)  ;

                               =   2/3 ;

                             

                               =   " \frac{2}{3} "

 

                              →  which is our answer.

____________________________________________

 Or:   " 0.6666... "  =  666 ÷ 999 = ?  ;

                        using calculator :

                               =  0.66666667 ;  

        →  which is the "rounded off" number of "0.6666..." ;

                                                                — (infinitely repeating) ;

                  →   So 666 ÷ 999 =

                  →   "  \frac{666}{999} " ;

               

                               =  " \frac{2}{3} " ;  

                               →  Either use a "fraction calculator" ;

       or simplify as aforementioned.    

____________________________________________

Hope this answer is helpful to you!

       Best wishes to you in your academic pursuits

              — and within the "Brainly" community!

____________________________________________

erastova [34]2 years ago
5 0

Answer:

2/3

Step-by-step explanation:

The correct answer would be 2/3. Since .333333334 is 1/3 since if you divided 1 over 3 it would be .33334. And since 0.6666 is double that you would just add one more number to the numerator!

I hope this helps! Please mark as brainliest! Good luck! :D

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Merta reports that 74% of its trains are on time. A check of 60 randomly selected trains shows that 38 of them arrived on time.
kenny6666 [7]

Answer:

No, the on-time rate of 74% is not correct.

Solution:

As per the question:

Sample size, n = 60

The proportion of the population, P' = 74% = 0.74

q' = 1 - 0.74 = 0.26

We need to find the probability that out of 60 trains, 38 or lesser trains arrive on time.

Now,

The proportion of the given sample, p = \frac{38}{60} = 0.634

Therefore, the probability is given by:

P(p\leq 0.634) = [\frac{p - P'}{\sqrt{\frac{P'q'}{n}}}]\leq [\frac{0.634 - 0.74}{\sqrt{\frac{0.74\times 0.26}{60}}}]

P(p\leq 0.634) = P[z\leq -1.87188]

P(p\leq 0.634) = P[z\leq -1.87] = 0.0298

Therefore, Probability of the 38 or lesser trains out of 60 trains to be on time is 0.0298 or 2.98 %

Thus the on-time rate of 74% is incorrect.

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What is 1/6d+2/3 = 1/4(d-2)
GenaCL600 [577]
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First, simplify \frac{1}{6} d to \frac{d}{6} / Your problem should look like: \frac{d}{6} + \frac{2}{3} = \frac{1}{4} (d - 2)
Second, simplify \frac{1}{4} (d - 2) to \frac{d-2}{4} / Your problem should look like: \frac{d}{6} + \frac{2}{3} = \frac{d-2}{4}
Third, multiply both sides by 12 (the LCM of 6,4) / Your problem should look like: 2d + 8 = 3(d - 2)
Fourth, expand. / Your problem should look like: 2d + 8 = 3d - 6
Fifth, subtract 2d from both sides. / Your problem should look like: 8 = 3d - 6 - 2d
Sixth, simplify 3d - 6 - 2d to d - 6 / Your problem should look like: 8 = d - 6
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I need help with this ​
kotegsom [21]

Answer:

Here is the summary of true statements:

A) The statement of the function modeled is (0, 3) is TRUE.

D) the equation for the line function is y = 2x+3 is TRUE.

E) the given table represents the linear function is TRUE

Step-by-step explanation:

Given the table

x   1      3      5      7

y   5      9      13     17

E)

It is clear that there is a CONSTANT CHANGE in the x and y values of the graph.

THE CONSTANT CHANGE IN X VALUES

i.e. 3-1=2, 5-3=2, 7-5=2

THE CONSTANT CHANGE IN Y VALUES

i.e. 9-5 = 4, 13 - 9 = 4, 17 - 13 = 4

Thus, the given table represents the linear function is TRUE

B)

It is clear that the value of y increase as the value of x increases.

Thus, the statement ''the value of y decreases as the value of x increases'' is FALSE!

D)

We know that the slop-intercept form of the line equation is

y = mx+b

where m is the slope and b is the y-intercept.

Determining the equation

Taking two points

(1, 5)

(3, 9)

Finding the slope between (1, 5) and (3, 9)

Using the formula

Slope = m =  [y₂ - y₁] /  [x₂ - x₁]

               =  [9 - 5] / [3 - 1]

               = 4 / 2  

               = 2

Thus, the slope of the line = m = 2

now substituting m = 2 and the point (1, 5) to determine the y-intercept

y = mx+b

5 = 2(1) + b

b = 5-2

b = 3

Thus, the value of y-intercept b = 3

substituting b = 3 and m = 2 in the slope-intercept form

y = mx+b

y = 2x+3

Therefore, the equation for the line function is y = 2x+3 is TRUE

A)

We know that the value of the y-intercept can be determined by setting x = 0, and determining the corresponding value of y.

We already know that the y-intercept b = 3

It means the y-intercept modeled is (0, 3)

Therefore, the statement of the function modeled is (0, 3) is TRUE.

C)

We have already got the equation

y = 2x+3

substituting x = 8

y = 2(8)+3

y = 10+3

y = 13

so at x = 8, the value of y = 13

Therefore, the statement that the ''On a graph of the function when x = 8, the value of y will be 2'' is FALSE!

Conclusion:

Here is the summary of true statements:

A) The statement of the function modeled is (0, 3) is TRUE.

D) the equation for the line function is y = 2x+3 is TRUE.

E) the given table represents the linear function is TRUE

3 0
2 years ago
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