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Anna11 [10]
3 years ago
13

This is the first half of the other question I asked

Engineering
1 answer:
Elodia [21]3 years ago
6 0

Answer: 8/3

Explanation:

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What information is usually gathered during vehicle crash tests?
aleksley [76]
Time, distance, damage
7 0
3 years ago
Some designers suggest that speech recognition should be used in a telephone menu system. This would allow users to interact wit
Ghella [55]

The designers suggest that speech recognition allows for spoken interaction or conversation and spoken prompts or commands.

Explanation:

The speech recognition is used when the user has physical impairments and hands are busy, eyes are occupied and the user cannot read.

We can save time with the usage of speech recognition system. The users are knowledgeable based on the actions available.

The problems faced in speech recognition system are in the noisy environment it has bad microphones and the commands should be learned and remembered.

The other obstacle is error correction is time consuming. the speech production has slow space to speech output provides privacy in public spaces. The disadvantage is it contains large amount of information.

5 0
4 years ago
Hi all, could you solve this please?<br> What is the value of the resistance R
Kazeer [188]

Answer:

try to 36v power and take 1a and intersect to 3

5 0
3 years ago
A binary star system consists of two stars of masses m1m1m_1 and m2m2m_2. The stars, which gravitationally attract each other, r
d1i1m1o1n [39]

Answer:

          a_c_2=\dfrac{a_c_1\times m_1}{m_2}

Explanation:

The question is: <em>Find the magnitude of the centripetal acceleration of the star with mass m₂</em>

The <em>centripetal acceleration</em> is the quotient of the centripetal force and the mass.

                a_c=\dfrac{F_c}{m}

Thus, you can write the equations for each star:

     

       a_c_1=\dfrac{F_c_1}{m_1}

       a_c_2=\dfrac{F_c_2}{m_2}

As per Newton's third law, the centripetal forces are equal in magnitude. Then:

       a_c_1\times m_1=a_c_2\times m_2

Now you can clear a_c_2:

          a_c_2=\dfrac{a_c_1\times m_1}{m_2}

6 0
4 years ago
7.13 An intersection approach has a saturation flow rate of 1500 veh/h, and vehicles arrive at the approach at the rate of 800 v
Naddik [55]

Answer:

23.34 seconds

Explanation:

Flow rate = 1500

Arrival = 800 vehicle per hour

Cycle c = 60 seconds

Dissipation time = 10 seconds

Arrival time = 800/3600 = 0.2222

Rate of departure = 1500/3600 = 0.4167

Traffic density p = 0.2222/0.4167 = 0.5332

Real time = r

r + to + 10 = c

to = c-r-10 ----1

t0 = p*r/1-p ----2

Equate both 1 and 2

C-r-10 = p*r/1-p

60-r-10 = 0.5332r/1-0.5332

50-r = 0.5332r/0.4668

50-r = 1.1422r

50 = 1.1422r + r

50 = 2.1422r

r = 50/2.1422

r = 23.34 seconds

7 0
3 years ago
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