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otez555 [7]
3 years ago
10

Consider a 50-mH inductor. a. Express the voltage across the inductor and then evaluate it at t = 0.25 s if iL (t) = 5e −2t + 3t

e−2t −2 A. Be certain to simplify your expression.
Engineering
1 answer:
IrinaK [193]3 years ago
3 0

Answer:

V=L(di/dt) where i is current, V=0.208

Explanation:

using expression iL(t)=5e-2t+3te-2t-2 and L=0.05H(50/1000)

V=0.05*d(5e-2t+3te-2t-2)/dt

since there is no power of e, I'll assume the power to be 1

V=0.05*(-2+3e-2)

at t=0.25

V=0.15e-0.2

V=0.208

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A platinum resistance temperature detector has a resistance of 100.00 V at 0°C, 138.50 V at 100°C and 175.83 V at 200°C. What wi
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The gage pressure measured as 2.2 atm, the absolute pressure of gas is 3.2 bar. Please determine the local atmospheric pressure
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Answer:

97.085\ \text{kPa}

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The local atmospheric pressure is 97.085\ \text{kPa}.

8 0
3 years ago
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