Answer:
NOT WISE
Explanation:
given,
T₁ = 87⁰C = 273 + 87 = 360 K
T₂ = 27⁰C = 273 + 27 = 300 K
work output given = 10 J
efficiency will be equal to :
output delivery = η ₓ input
= 0.166 ₓ 40
= 6.66 J
hence, the output of new engine is less than the old one so, investing in new engine will not be feasible.
Answer:
The escape systems not working
Answer:
-Differential equation: d²T/dx² = 0
-The boundary conditions are;
1) Heat flux at bottom;
-KAdT(0)/dx = ηq_e
2) Heat flux at top surface;
-KdT(L)/dx = h(T(L) - T(water))
Explanation:
To solve this question, let's work with the following assumptions that we are given;
- Heat transfer is steady and one dimensional
- Thermal conductivity is constant.
- No heat generation exists in the medium
- The top surface which is at x = L will be subjected to convection while the bottom surface which is at x = 0 will be subjected to uniform heat flux.
Will all those assumptions given, the differential equation can be expressed as; d²T/dx² = 0
Now the boundary conditions are;
1) Heat flux at bottom;
q(at x = 0) is;
-KAdT(0)/dx = ηq_e
2) Heat flux at top surface;
q(at x = L):
-KdT(L)/dx = h(T(L) - T(water))
Answer:
W = - 523.425 W = -0.5234 kW
Negative sign show power input to the pump
Explanation:
By using energy balanced at state q and state 2
As it is given neglect kinetic energy and heat transfer therefore above equation rduece to
As temp remain cosntant , so enthalapy difference is givena s
from saturated water tables, for temperature 15 degree celcius specific volume of water is
putting zi =0, z2 = 15, m= 1.5 kg/s
W = - 523.425 W
Negative sign show power input to the pump