Ask question

Ask question

All categories

3 years ago

9

Plz help me with it !

1 answer:

Kipish [7]3 years ago

8 0

Answer: $\bold{-7+2\sqrt{14}+5\sqrt{7}-10\sqrt{2}}$

<u>Step-by-step explanation:</u>

$\dfrac{\sqrt7-5}{\sqrt7+\sqrt8}\bigg(\dfrac{\sqrt7-\sqrt8}{\sqrt7-\sqrt8}\bigg)=\dfrac{7-2\sqrt{14}-5\sqrt{7}+10\sqrt2}{7-8}=\dfrac{7-2\sqrt{14}-5\sqrt{7}+10\sqrt2}{-1}\\\\\\=\boxed{-7+2\sqrt{14}+5\sqrt{7}-10\sqrt2}$

You might be interested in

Please Help!!! . . . . .

Ede4ka [16]

PEMDAS. parenthesis, exponents, multiple or divide (whichever come first from left to right), add or subtract (whichever comes first from left to right)

So first do stuff in parenthesis.
Then do divide because thats next on the list and it happens earlier than the multiply one.

So, A

8 0

2 years ago

What statements must be true of an equation before you can use quadratic formula?

Alexus [3.1K]

Before you use the quadratic formula, you have to make sure the equation itself is a quadratic and that a and b are not 0.

3 0

3 years ago

34 divided by 3 3/4 equals what in fraction form

anygoal [31]

Answer:

9.06

Step-by-step explanation:

6 0

3 years ago

melisa1 [442]

Answer:

$sin O=\dfrac{3\sqrt{13}}{13}\\cos O=\dfrac{2\sqrt{13}}{13}\\tan O=\dfrac{3}{2}$

Step-by-step explanation:

If the point (2,3) is on the terminal side of an angle in standard position.

Adjacent of O, x=2,

Opposite of O, y=3

Next, we determine the hypotenuse, r using Pythagoras Theorem.

$Hypotenuse =\sqrt{Opposite^2+Adjacent^2} \\r=\sqrt{3^2+2^2} \\r=\sqrt{13}$

Therefore:

$sin O=\dfrac{Opposite}{Hypotenuse} \\sin O=\dfrac{3}{\sqrt{13}} \\$Rationalizing\\sin O=\dfrac{3\sqrt{13}}{13}$

$cos O=\dfrac{Adjacent}{Hypotenuse} \\cos O=\dfrac{2}{\sqrt{13}} \\$Rationalizing\\cos O=\dfrac{2\sqrt{13}}{13}$

$Tan O=\dfrac{Opposite}{Adjacent} \\tan O=\dfrac{3}{2}$

4 0

3 years ago

Problem 2-11 (Algorithmic) Let A be an event that a person's primary method of transportation to and from work is an automobile

dangina [55]

The events are mutually exclusive, because your primary method can't be both a driving a car or taking a bus.

Since they are exclusive, the probability of the "or" clause is the sum of the probabilities:

$P(A\lor B)=P(A)+P(B)=0.48+0.32=0.8$

Since a person primarily takes a bus with probability 0.32, the opposite happens with probability

$1-P(B) = 1-0.32=0.68$

7 0

3 years ago